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Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.
- a)Mixture of o and - m - bromotoluenes
- b)Mixture of o - and p - dibromotoluenes
- c)Mixture of o - and p - bromoanilines
- d)Mixture of o - and p - bromotoluenes
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Toluene is nitrated and the resulting product is reduced with tin and ...
To understand the reaction sequence and the formation of the final product, let's break it down step by step:
1. Nitration of Toluene:
Toluene (C6H5CH3) is treated with a mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4) to undergo nitration. In this reaction, the methyl group (CH3) of toluene is substituted by a nitro group (-NO2), resulting in the formation of methyl nitrobenzene.
2. Reduction of Methyl Nitrobenzene:
The methyl nitrobenzene obtained from the previous step is then reduced using a reducing agent such as tin (Sn) and hydrochloric acid (HCl). This reduction converts the nitro group (-NO2) to an amino group (-NH2), yielding methyl aniline.
3. Diazotization of Methyl Aniline:
The methyl aniline obtained from the previous step is mixed with sodium nitrite (NaNO2) and hydrochloric acid (HCl) to undergo diazotization. In this process, the amino group (-NH2) of methyl aniline is converted into a diazonium salt (-N2+), while the byproduct is water (H2O).
4. Sandmeyer Reaction with Copper Bromide:
The diazonium salt formed in the previous step is then treated with copper bromide (CuBr) and heated. This reaction is known as the Sandmeyer reaction. The diazonium salt is decomposed, and the benzene ring undergoes substitution with a bromine atom (Br). The bromine atom can substitute at either the ortho (o) or para (p) positions, resulting in the formation of o-bromotoluene and p-bromotoluene.
5. Final Product:
The final product obtained from the reaction sequence described above is a mixture of o-bromotoluene and p-bromotoluene. These compounds have a bromine atom substituted at either the ortho or para positions of the toluene ring.
Hence, the correct answer is option 'D' - a mixture of o- and p-bromotoluenes.
1. Nitration of Toluene:
Toluene (C6H5CH3) is treated with a mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4) to undergo nitration. In this reaction, the methyl group (CH3) of toluene is substituted by a nitro group (-NO2), resulting in the formation of methyl nitrobenzene.
2. Reduction of Methyl Nitrobenzene:
The methyl nitrobenzene obtained from the previous step is then reduced using a reducing agent such as tin (Sn) and hydrochloric acid (HCl). This reduction converts the nitro group (-NO2) to an amino group (-NH2), yielding methyl aniline.
3. Diazotization of Methyl Aniline:
The methyl aniline obtained from the previous step is mixed with sodium nitrite (NaNO2) and hydrochloric acid (HCl) to undergo diazotization. In this process, the amino group (-NH2) of methyl aniline is converted into a diazonium salt (-N2+), while the byproduct is water (H2O).
4. Sandmeyer Reaction with Copper Bromide:
The diazonium salt formed in the previous step is then treated with copper bromide (CuBr) and heated. This reaction is known as the Sandmeyer reaction. The diazonium salt is decomposed, and the benzene ring undergoes substitution with a bromine atom (Br). The bromine atom can substitute at either the ortho (o) or para (p) positions, resulting in the formation of o-bromotoluene and p-bromotoluene.
5. Final Product:
The final product obtained from the reaction sequence described above is a mixture of o-bromotoluene and p-bromotoluene. These compounds have a bromine atom substituted at either the ortho or para positions of the toluene ring.
Hence, the correct answer is option 'D' - a mixture of o- and p-bromotoluenes.
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Toluene is nitrated and the resulting product is reduced with tin and ...
The reaction Sequence is as Follows :
When a diazonium salt is treated with copper (I) chloride (Cu2Cl2) or copper (I) bromide (Cu2Br2), the corresponding haloarene is formed. This reaction is known as Sandmeyer reaction. It is used for introducing a chloro or bromo group in the benzene ring.
When a diazonium salt is treated with copper (I) chloride (Cu2Cl2) or copper (I) bromide (Cu2Br2), the corresponding haloarene is formed. This reaction is known as Sandmeyer reaction. It is used for introducing a chloro or bromo group in the benzene ring.
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Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer?
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Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer?.
Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is mixed with NaNO2/HCl and CuBr and then heated, the product so formed contains.a)Mixture of o and - m - bromotoluenesb)Mixture of o - and p - dibromotoluenesc)Mixture of o - and p - bromoanilinesd)Mixture of o - and p - bromotoluenesCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
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