A campaign is started by volunteers of mathematical club to boost scho...
Proof of ∆ABC ≅ ∆CEA given ∆ABC ≅ ∆ECD and BC = AE
Step 1: Draw a diagram
Before proving this, let's draw a diagram to understand the given conditions and what we need to prove.
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Step 2: Write down the given conditions
The given conditions are:
Step 3: Identify the common sides and angles
Since ∆ABC ≅ ∆ECD, we know that the corresponding angles and sides are equal. Therefore, we can identify the following common sides and angles:
- ∠ABC = ∠ECD (corresponding angles)
- ∠BCA = ∠CDE (corresponding angles)
- BC = CD (corresponding sides)
- AC = CE (corresponding sides)
Step 4: Prove ∆ABC ≅ ∆CEA
We need to prove that ∆ABC ≅ ∆CEA. We can do this by showing that all corresponding sides and angles are equal. Let's start with the sides:
- AB = CD (corresponding sides, since ∆ABC ≅ ∆ECD)
- BC = BC (common side)
- AC = CE (corresponding sides, since BC = AE)
Therefore, we have shown that all corresponding sides are equal. Now, let's move on to the angles:
- ∠ABC = ∠ECD (corresponding angles, since ∆ABC ≅ ∆ECD)
- ∠BCA = ∠CDE (corresponding angles, since ∆ABC ≅ ∆ECD)
- ∠ACB = ∠AEC (vertical angles)
Therefore, we have shown that all corresponding angles are equal.
Since all corresponding sides and angles are equal, we can conclude that ∆ABC ≅ ∆CEA.
Step 5: Conclusion
Therefore, we have proven that ∆ABC ≅ ∆CEA given ∆ABC ≅ ∆ECD and BC = AE. This implies that the logo made by the volunteers of the mathematical club is valid, and the campaign can continue to promote cleanliness and hygiene in the school and its surrounding areas under the Swachh Bharat Abhiyan.