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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor is
  • a)
    106m−3
  • b)
    108m−3
  • c)
    1010m−3
  • d)
    1012m−3
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A semiconductor has equal electron and hole concentration of 2 ×...
From the relation of equivalence of charge carrier in extrinsic and intrinsic carrier, we have nen= ni2 , where ne, n& ni represents electron density, hole density and number of intrinsic charge carrier density.
On substituting all the corresponding given values, we have
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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer?
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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer?.
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