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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor is
- a)106m−3
- b)108m−3
- c)1010m−3
- d)1012m−3
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A semiconductor has equal electron and hole concentration of 2 ×...
Understanding Semiconductor Doping
When a semiconductor is doped, it alters the balance of charge carriers (electrons and holes) in the material. Initially, we have equal concentrations of electrons and holes, both at 2 × 10^8 m–3.
Initial Conditions
- Electron concentration (n) = 2 × 10^8 m–3
- Hole concentration (p) = 2 × 10^8 m–3
Doping Effect
Upon doping with an impurity, the electron concentration increases to:
- New electron concentration (n') = 4 × 10^10 m–3
Charge Carrier Relationship
In intrinsic semiconductors, the product of electron and hole concentrations is constant, given by:
- n * p = ni² (where ni is the intrinsic carrier concentration)
After doping, the new relationship becomes:
- n' * p' = ni²
Given n' = 4 × 10^10 m–3, we need to find the new hole concentration (p').
Calculating the New Hole Concentration
Using the initial condition, we can calculate ni²:
- (2 × 10^8) * (2 × 10^8) = 4 × 10^16
Now, substitute into the relationship:
- (4 × 10^10) * p' = 4 × 10^16
Solving for p':
- p' = (4 × 10^16) / (4 × 10^10) = 10^6 m–3
Conclusion
Thus, the new hole concentration after doping is:
- p' = 10^6 m–3
The correct answer is option 'A', which is 10^6 m–3.
When a semiconductor is doped, it alters the balance of charge carriers (electrons and holes) in the material. Initially, we have equal concentrations of electrons and holes, both at 2 × 10^8 m–3.
Initial Conditions
- Electron concentration (n) = 2 × 10^8 m–3
- Hole concentration (p) = 2 × 10^8 m–3
Doping Effect
Upon doping with an impurity, the electron concentration increases to:
- New electron concentration (n') = 4 × 10^10 m–3
Charge Carrier Relationship
In intrinsic semiconductors, the product of electron and hole concentrations is constant, given by:
- n * p = ni² (where ni is the intrinsic carrier concentration)
After doping, the new relationship becomes:
- n' * p' = ni²
Given n' = 4 × 10^10 m–3, we need to find the new hole concentration (p').
Calculating the New Hole Concentration
Using the initial condition, we can calculate ni²:
- (2 × 10^8) * (2 × 10^8) = 4 × 10^16
Now, substitute into the relationship:
- (4 × 10^10) * p' = 4 × 10^16
Solving for p':
- p' = (4 × 10^16) / (4 × 10^10) = 10^6 m–3
Conclusion
Thus, the new hole concentration after doping is:
- p' = 10^6 m–3
The correct answer is option 'A', which is 10^6 m–3.
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A semiconductor has equal electron and hole concentration of 2 ×...
From the relation of equivalence of charge carrier in extrinsic and intrinsic carrier, we have nenh = ni2 , where ne, nh & ni represents electron density, hole density and number of intrinsic charge carrier density.
On substituting all the corresponding given values, we have
On substituting all the corresponding given values, we have
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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer?
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A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A semiconductor has equal electron and hole concentration of 2 × 108m−3 . On doping with a certain impurity, the electron concentration increases to 4 × 1010m−3 , then the new hole concentration of the semiconductor isa)106m−3b)108m−3c)1010m−3d)1012m−3Correct answer is option 'A'. Can you explain this answer?.
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