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Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².log x) C. X^x³ (x² - 3x².log x) D. None of these?
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Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².l...
Calculation of f'(y)


To find f'(y), we need to use the chain rule of differentiation.

Let u = x³, then y = X^u

Using the chain rule, we get

dy/dx = dy/du * du/dx

= X^u * 3x²

= X^x³ * 3x²

Therefore, f'(y) = X^x³ * 3x²

Answer


The correct answer is option A.

A. X³(x² + 3x.logx)

This is because f'(y) is equal to X^x³ * 3x².

Option B is incorrect because it has an extra x term in the second part of the expression.

Option C is also incorrect because it has a negative sign instead of a plus sign between the two terms.

None of these options are correct because they are not equal to X^x³ * 3x².

Therefore, the correct answer is A.
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Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².log x) C. X^x³ (x² - 3x².log x) D. None of these?
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Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².log x) C. X^x³ (x² - 3x².log x) D. None of these? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².log x) C. X^x³ (x² - 3x².log x) D. None of these? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let (y) = X^x³ then f '(y) is A. X³(x² 3x. logx) B. X^x³ (x² 3x².log x) C. X^x³ (x² - 3x².log x) D. None of these?.
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