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Suppose cos θ + sin θ = √2 cos θ, then which of the following is the correct value of cos θ - sin θ?
  • a)
    √2 cos θ
  • b)
    √2 sin θ
  • c)
    -√2 cos θ
  • d)
    -√2 sin θ
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Suppose cos θ + sin θ = √2 cos θ, then which o...
It is given that, cos θ + sin θ = √2 cos θ …..(i)
On squaring both sides, we will get,
(cos θ + sin θ)2 = (√2 cos θ)2
⇒ cos2 θ + sin2 θ + 2 sin θ cos θ = 2 cos2 θ
Or, 2cos2 θ - cos2 θ - sin2 θ = 2 sinθ cosθ
⇒ cos2 θ - sin2 θ = 2 sin θ cos θ
⇒ (cos θ + sin θ) (cos θ - sin θ) = 2 sin θ cos θ
⇒ (√2 cos θ) (cos θ - sin θ) = 2 sin θ cos θ [from equation (i)]
⇒ (cos θ - sin θ) = 2 sinθ cosθ / √2 cos θ
= √2 sin θ
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Most Upvoted Answer
Suppose cos θ + sin θ = √2 cos θ, then which o...
It is given that, cos θ + sin θ = √2 cos θ …..(i)
On squaring both sides, we will get,
(cos θ + sin θ)2 = (√2 cos θ)2
⇒ cos2 θ + sin2 θ + 2 sin θ cos θ = 2 cos2 θ
Or, 2cos2 θ - cos2 θ - sin2 θ = 2 sinθ cosθ
⇒ cos2 θ - sin2 θ = 2 sin θ cos θ
⇒ (cos θ + sin θ) (cos θ - sin θ) = 2 sin θ cos θ
⇒ (√2 cos θ) (cos θ - sin θ) = 2 sin θ cos θ [from equation (i)]
⇒ (cos θ - sin θ) = 2 sinθ cosθ / √2 cos θ
= √2 sin θ
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Community Answer
Suppose cos θ + sin θ = √2 cos θ, then which o...
It is given that, cos θ + sin θ = √2 cos θ …..(i)
On squaring both sides, we will get,
(cos θ + sin θ)2 = (√2 cos θ)2
⇒ cos2 θ + sin2 θ + 2 sin θ cos θ = 2 cos2 θ
Or, 2cos2 θ - cos2 θ - sin2 θ = 2 sinθ cosθ
⇒ cos2 θ - sin2 θ = 2 sin θ cos θ
⇒ (cos θ + sin θ) (cos θ - sin θ) = 2 sin θ cos θ
⇒ (√2 cos θ) (cos θ - sin θ) = 2 sin θ cos θ [from equation (i)]
⇒ (cos θ - sin θ) = 2 sinθ cosθ / √2 cos θ
= √2 sin θ
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Suppose cos θ + sin θ = √2 cos θ, then which of the following is the correct value of cos θ - sin θ?a)√2 cos θb)√2 sin θc)-√2 cos θd)-√2 sin θCorrect answer is option 'B'. Can you explain this answer?
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