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Max z= 3x1 2x2 2x1 x2 ≤ 2, 3X1 4x2 ≥ 12, x1 ≥ 0, x2 ≥ 0, solution is Ops: A. unique B. unbounded C. degenerate D. O infinite?
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Max z= 3x1 2x2 2x1 x2 ≤ 2, 3X1 4x2 ≥ 12, x1 ≥ 0, x2 ≥ 0, solution is O...
Linear Programming Problem


Given:

Max z = 3x1 + 2x2

2x1 + x2 ≤ 2

3x1 + 4x2 ≥ 12

x1 ≥ 0, x2 ≥ 0


To Find:

Whether the solution is:

A. Unique

B. Unbounded

C. Degenerate

D. Infinite


Solution:


Graphical Method:

Let's plot the given constraints on a graph.



From the above graph, we can see that the feasible region is bounded and the objective function line has a unique point of intersection with the feasible region.

Hence, the solution is Unique.


Simplex Method:

We can solve the given LP problem using the simplex method as well.

Let's convert the given LP problem into standard form:

Max z = 3x1 + 2x2

2x1 + x2 + x3 = 2

3x1 + 4x2 - x4 = 12

x1, x2, x3, x4 ≥ 0


Now, we can use the simplex method to solve the problem:










































Basic Variables x1 x2 x3 x4 Constants
x3 2 1 1 0 2
x4 3 4 0 -1 12
Zj 3 2 0 0
Cj - Zj 0 0 2 0


Since all the values in the last row are non-negative, we have reached the optimal solution.
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Max z= 3x1 2x2 2x1 x2 ≤ 2, 3X1 4x2 ≥ 12, x1 ≥ 0, x2 ≥ 0, solution is Ops: A. unique B. unbounded C. degenerate D. O infinite?
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