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Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)?
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Determine the best feasible solution for the below LP problem: min z= ...
X2 ≥ 0
To solve the LP problem, we can use the graphical method by plotting the feasible region and finding the corner points.
First, we plot the constraints:
2x1 + x2 ≥ 10 (red line)
-3x1 + 2x2 ≤ 6 (blue line)
x1 x2 ≥ 6 (green line)
x1, x2 ≥ 0 (quadrant 1)
The feasible region is the shaded area:
The corner points of the feasible region are:
A: (2, 6)
B: (2, 3)
C: (3, 2)
D: (6, 1)
E: (6, 2)
Next, we evaluate the objective function z = 4x1 + 3x2 at each corner point:
A: z = 4(2) + 3(6) = 26
B: z = 4(2) + 3(3) = 14
C: z = 4(3) + 3(2) = 18
D: z = 4(6) + 3(1) = 27
E: z = 4(6) + 3(2) = 30
The smallest value of z is at point B: z = 14.
Therefore, the best feasible solution for the LP problem is x1 = 2, x2 = 3, with a minimum value of z = 14.
To solve the LP problem, we can use the graphical method by plotting the feasible region and finding the corner points.
First, we plot the constraints:
2x1 + x2 ≥ 10 (red line)
-3x1 + 2x2 ≤ 6 (blue line)
x1 x2 ≥ 6 (green line)
x1, x2 ≥ 0 (quadrant 1)
The feasible region is the shaded area:
The corner points of the feasible region are:
A: (2, 6)
B: (2, 3)
C: (3, 2)
D: (6, 1)
E: (6, 2)
Next, we evaluate the objective function z = 4x1 + 3x2 at each corner point:
A: z = 4(2) + 3(6) = 26
B: z = 4(2) + 3(3) = 14
C: z = 4(3) + 3(2) = 18
D: z = 4(6) + 3(1) = 27
E: z = 4(6) + 3(2) = 30
The smallest value of z is at point B: z = 14.
Therefore, the best feasible solution for the LP problem is x1 = 2, x2 = 3, with a minimum value of z = 14.
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Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)?
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Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)?.
Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the best feasible solution for the below LP problem: min z= 4x1 3x2, 2x1 x2≥ 10,-3x1 2x2≤6,x1 x2≥ 6,x1 &x2 ≥ 0 A. (4,2) Ops: B. (2,4) c. (5,2) D. (2,5)?.
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