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The length of a machined part is known to have a normal distribution with a mean of 100mm and standard deviation of 2mm. What proportion of the parts will be above 103.3 mm? P(Z≤1.65)=0.9505 Ops: A. 0.0651 B. 0.0495 C. 0.0583 D. 0.0318?
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The length of a machined part is known to have a normal distribution w...
Solution:

Given: μ = 100mm, σ = 2mm, x = 103.3mm

We need to find P(X > 103.3mm)

Step 1: Standardize the value of X using the formula:

z = (x - μ) / σ

z = (103.3 - 100) / 2

z = 1.65

Step 2: Find the proportion of parts above 103.3mm using the standard normal distribution table or calculator:

P(Z > 1.65) = 1 - P(Z ≤ 1.65) (since we want the area to the right of z-score)

P(Z > 1.65) = 1 - 0.9505

P(Z > 1.65) = 0.0495

Therefore, the proportion of the parts that will be above 103.3 mm is 0.0495 or 4.95%.

Answer: Option B. 0.0495
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The length of a machined part is known to have a normal distribution with a mean of 100mm and standard deviation of 2mm. What proportion of the parts will be above 103.3 mm? P(Z≤1.65)=0.9505 Ops: A. 0.0651 B. 0.0495 C. 0.0583 D. 0.0318?
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The length of a machined part is known to have a normal distribution with a mean of 100mm and standard deviation of 2mm. What proportion of the parts will be above 103.3 mm? P(Z≤1.65)=0.9505 Ops: A. 0.0651 B. 0.0495 C. 0.0583 D. 0.0318? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about The length of a machined part is known to have a normal distribution with a mean of 100mm and standard deviation of 2mm. What proportion of the parts will be above 103.3 mm? P(Z≤1.65)=0.9505 Ops: A. 0.0651 B. 0.0495 C. 0.0583 D. 0.0318? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The length of a machined part is known to have a normal distribution with a mean of 100mm and standard deviation of 2mm. What proportion of the parts will be above 103.3 mm? P(Z≤1.65)=0.9505 Ops: A. 0.0651 B. 0.0495 C. 0.0583 D. 0.0318?.
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