Software Development Exam > Software Development Questions > Consider the following SQL code:CREATE TABLE ...
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Consider the following SQL code:
CREATE TABLE Employees (
EmployeeID INT PRIMARY KEY,
FirstName VARCHAR(50),
LastName VARCHAR(50),
DepartmentID INT
);
EmployeeID INT PRIMARY KEY,
FirstName VARCHAR(50),
LastName VARCHAR(50),
DepartmentID INT
);
INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)
VALUES (1, 'John', 'Doe', 101),
(2, 'Jane', 'Smith', 102),
(3, 'Alice', 'Johnson', 101);
VALUES (1, 'John', 'Doe', 101),
(2, 'Jane', 'Smith', 102),
(3, 'Alice', 'Johnson', 101);
SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;
What is the output of the above code?
What is the output of the above code?
- a)No output
- b)Error
- c)101, 2 102, 1
- d)2, 1 3, 1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider the following SQL code:CREATE TABLE Employees ( EmployeeID IN...
The code creates a table named "Employees" with four columns: EmployeeID, FirstName, LastName, and DepartmentID. It then inserts three rows into the table. The SELECT statement with GROUP BY DepartmentID counts the number of employees in each department. In this case, there are 2 employees in department 101 and 1 employee in department 102.
Most Upvoted Answer
Consider the following SQL code:CREATE TABLE Employees ( EmployeeID IN...
Output of the SQL code:
The output of the above SQL code will be:
- 101, 2
- 102, 1
Explanation:
Let's break down the SQL code step by step to understand the output:
1. CREATE TABLE Employees:
- This statement creates a table called "Employees" with the following columns:
- EmployeeID (integer, primary key)
- FirstName (varchar with a maximum length of 50 characters)
- LastName (varchar with a maximum length of 50 characters)
- DepartmentID (integer)
2. INSERT INTO Employees:
- This statement inserts three rows of data into the "Employees" table.
- Each row represents an employee with their respective EmployeeID, FirstName, LastName, and DepartmentID.
3. SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID:
- This statement retrieves data from the "Employees" table.
- It selects the DepartmentID column and counts the number of occurrences for each unique DepartmentID.
- The GROUP BY clause groups the results by DepartmentID.
The output of this SELECT statement will be:
- 101, 2: This indicates that there are two employees in the department with ID 101.
- 102, 1: This indicates that there is one employee in the department with ID 102.
Therefore, the final output of the above SQL code will be "101, 2" and "102, 1".
The output of the above SQL code will be:
- 101, 2
- 102, 1
Explanation:
Let's break down the SQL code step by step to understand the output:
1. CREATE TABLE Employees:
- This statement creates a table called "Employees" with the following columns:
- EmployeeID (integer, primary key)
- FirstName (varchar with a maximum length of 50 characters)
- LastName (varchar with a maximum length of 50 characters)
- DepartmentID (integer)
2. INSERT INTO Employees:
- This statement inserts three rows of data into the "Employees" table.
- Each row represents an employee with their respective EmployeeID, FirstName, LastName, and DepartmentID.
3. SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID:
- This statement retrieves data from the "Employees" table.
- It selects the DepartmentID column and counts the number of occurrences for each unique DepartmentID.
- The GROUP BY clause groups the results by DepartmentID.
The output of this SELECT statement will be:
- 101, 2: This indicates that there are two employees in the department with ID 101.
- 102, 1: This indicates that there is one employee in the department with ID 102.
Therefore, the final output of the above SQL code will be "101, 2" and "102, 1".
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Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer?
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Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer?.
Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Employees ( EmployeeID INT PRIMARY KEY, FirstName VARCHAR(50), LastName VARCHAR(50), DepartmentID INT);INSERT INTO Employees (EmployeeID, FirstName, LastName, DepartmentID)VALUES (1, John, Doe, 101), (2, Jane, Smith, 102), (3, Alice, Johnson, 101);SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;What is the output of the above code?a)No outputb)Errorc)101, 2 102, 1d)2, 1 3, 1Correct answer is option 'C'. Can you explain this answer?.
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