Software Development Exam > Software Development Questions > Consider the following SQL code:CREATE TABLE ...
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Consider the following SQL code:
CREATE TABLE Students (
StudentID INT PRIMARY KEY,
Name VARCHAR(50),
Marks INT
);
StudentID INT PRIMARY KEY,
Name VARCHAR(50),
Marks INT
);
INSERT INTO Students (StudentID, Name, Marks)
VALUES (1, 'Alice', 90),
(2, 'Bob', 80),
(3, 'Charlie', 95);
VALUES (1, 'Alice', 90),
(2, 'Bob', 80),
(3, 'Charlie', 95);
SELECT AVG(Marks) FROM Students;
What is the output of the above code?
- a)No output
- b)Error
- c)88.33
- d)90.00
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Consider the following SQL code:CREATE TABLE Students ( StudentID INT ...
Solution:
The given SQL code creates a table named "Students" with three columns: StudentID, Name, and Marks. The StudentID column is defined as the primary key, ensuring uniqueness for each student. The Name column is of type VARCHAR(50), allowing a maximum of 50 characters, and the Marks column is of type INT.
The code then inserts three rows into the Students table, each representing a student with their respective ID, name, and marks.
Finally, the code executes a SELECT statement to calculate the average marks of all the students in the table.
The output of the above SQL code is 88.33.
Explanation:
The SELECT statement uses the AVG() function to calculate the average of the Marks column in the Students table. The AVG() function is an aggregate function that returns the average value of a numeric column. In this case, it calculates the average of the Marks column.
The AVG() function calculates the average by summing up all the values in the column and dividing the sum by the total number of rows. In this case, the sum of the marks is 90 + 80 + 95 = 265, and the total number of rows is 3.
Therefore, the average marks is calculated as 265 / 3 = 88.33.
Hence, the output of the above SQL code is 88.33.
Note: The output is not rounded to two decimal places as mentioned in option C. The exact average value is 88.33.
The given SQL code creates a table named "Students" with three columns: StudentID, Name, and Marks. The StudentID column is defined as the primary key, ensuring uniqueness for each student. The Name column is of type VARCHAR(50), allowing a maximum of 50 characters, and the Marks column is of type INT.
The code then inserts three rows into the Students table, each representing a student with their respective ID, name, and marks.
Finally, the code executes a SELECT statement to calculate the average marks of all the students in the table.
The output of the above SQL code is 88.33.
Explanation:
The SELECT statement uses the AVG() function to calculate the average of the Marks column in the Students table. The AVG() function is an aggregate function that returns the average value of a numeric column. In this case, it calculates the average of the Marks column.
The AVG() function calculates the average by summing up all the values in the column and dividing the sum by the total number of rows. In this case, the sum of the marks is 90 + 80 + 95 = 265, and the total number of rows is 3.
Therefore, the average marks is calculated as 265 / 3 = 88.33.
Hence, the output of the above SQL code is 88.33.
Note: The output is not rounded to two decimal places as mentioned in option C. The exact average value is 88.33.
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Community Answer
Consider the following SQL code:CREATE TABLE Students ( StudentID INT ...
The code creates a table named "Students" with three columns: StudentID, Name, and Marks. It then inserts three rows into the table. The SELECT statement with AVG(Marks) calculates the average value of the Marks column, which is (90 + 80 + 95) / 3 = 88.33.
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Consider the following SQL code:CREATE TABLE Students ( StudentID INT PRIMARY KEY, Name VARCHAR(50), Marks INT);INSERT INTO Students (StudentID, Name, Marks)VALUES (1, Alice, 90), (2, Bob, 80), (3, Charlie, 95);SELECT AVG(Marks) FROM Students;What is the output of the above code?a)No outputb)Errorc)88.33d)90.00Correct answer is option 'C'. Can you explain this answer?
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