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Consider the following SQL code:
CREATE TABLE Orders (
OrderID INT PRIMARY KEY,
CustomerID INT,
TotalAmount DECIMAL(10, 2),
OrderDate DATE
);
OrderID INT PRIMARY KEY,
CustomerID INT,
TotalAmount DECIMAL(10, 2),
OrderDate DATE
);
INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)
VALUES (1, 101, 100.50, '2023-05-01'),
(2, 102, 200.75, '2023-05-02'),
(3, 103, 150.20, '2023-05-03');
VALUES (1, 101, 100.50, '2023-05-01'),
(2, 102, 200.75, '2023-05-02'),
(3, 103, 150.20, '2023-05-03');
SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;
What is the output of the above code?
What is the output of the above code?
- a)No output
- b)Error
- c)101, 100.50 102, 200.75 103, 150.20
- d)452.45
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIM...
The code creates a table named "Orders" with four columns: OrderID, CustomerID, TotalAmount, and OrderDate. It then inserts three rows into the table. The SELECT statement with GROUP BY CustomerID calculates the sum of TotalAmount for each customer. In this case, the output will include the customer ID and the corresponding sum of TotalAmount for each customer.
Most Upvoted Answer
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIM...
Output of the SQL code:
The output of the above SQL code will be:
101, 100.50
102, 200.75
103, 150.20
Explanation:
Let's break down the SQL code and understand how it produces the above output.
1. CREATE TABLE:
The first line of the code creates a table called "Orders" with four columns:
- OrderID (integer) - the primary key of the table
- CustomerID (integer) - the ID of the customer associated with the order
- TotalAmount (decimal) - the total amount of the order
- OrderDate (date) - the date when the order was placed
2. INSERT INTO:
The next three lines of the code insert three rows into the "Orders" table:
- OrderID 1, CustomerID 101, TotalAmount 100.50, OrderDate 2023-05-01
- OrderID 2, CustomerID 102, TotalAmount 200.75, OrderDate 2023-05-02
- OrderID 3, CustomerID 103, TotalAmount 150.20, OrderDate 2023-05-03
3. SELECT statement:
The last line of the code executes a SELECT statement to retrieve data from the "Orders" table. It selects two columns: CustomerID and the sum of TotalAmount. The data is grouped by CustomerID using the GROUP BY clause.
4. Output:
The output of the SELECT statement will be the sum of TotalAmount for each CustomerID. In this case, the output will be:
- CustomerID 101, TotalAmount 100.50
- CustomerID 102, TotalAmount 200.75
- CustomerID 103, TotalAmount 150.20
Conclusion:
The output of the SQL code will be the CustomerID and the sum of TotalAmount for each customer. In this case, the output will be: 101, 100.50 102, 200.75 103, 150.20.
The output of the above SQL code will be:
101, 100.50
102, 200.75
103, 150.20
Explanation:
Let's break down the SQL code and understand how it produces the above output.
1. CREATE TABLE:
The first line of the code creates a table called "Orders" with four columns:
- OrderID (integer) - the primary key of the table
- CustomerID (integer) - the ID of the customer associated with the order
- TotalAmount (decimal) - the total amount of the order
- OrderDate (date) - the date when the order was placed
2. INSERT INTO:
The next three lines of the code insert three rows into the "Orders" table:
- OrderID 1, CustomerID 101, TotalAmount 100.50, OrderDate 2023-05-01
- OrderID 2, CustomerID 102, TotalAmount 200.75, OrderDate 2023-05-02
- OrderID 3, CustomerID 103, TotalAmount 150.20, OrderDate 2023-05-03
3. SELECT statement:
The last line of the code executes a SELECT statement to retrieve data from the "Orders" table. It selects two columns: CustomerID and the sum of TotalAmount. The data is grouped by CustomerID using the GROUP BY clause.
4. Output:
The output of the SELECT statement will be the sum of TotalAmount for each CustomerID. In this case, the output will be:
- CustomerID 101, TotalAmount 100.50
- CustomerID 102, TotalAmount 200.75
- CustomerID 103, TotalAmount 150.20
Conclusion:
The output of the SQL code will be the CustomerID and the sum of TotalAmount for each customer. In this case, the output will be: 101, 100.50 102, 200.75 103, 150.20.
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Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer?
Question Description
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer?.
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer?.
Solutions for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development.
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Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)101, 100.50 102, 200.75 103, 150.20d)452.45Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Software Development tests.
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