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Consider the following SQL code:
CREATE TABLE Orders (
OrderID INT PRIMARY KEY,
CustomerID INT,
TotalAmount DECIMAL(10, 2),
OrderDate DATE
);
OrderID INT PRIMARY KEY,
CustomerID INT,
TotalAmount DECIMAL(10, 2),
OrderDate DATE
);
INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)
VALUES (1, 101, 100.50, '2023-05-01'),
(2, 102, 200.75, '2023-05-02'),
(3, 103, 150.20, '2023-05-03');
VALUES (1, 101, 100.50, '2023-05-01'),
(2, 102, 200.75, '2023-05-02'),
(3, 103, 150.20, '2023-05-03');
SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;
What is the output of the above code?
What is the output of the above code?
- a)No output
- b)Error
- c)'Jane', 60000.00 'Alice', 70000.00
- d)'Alice', 70000.00
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIM...
The code creates a table named "Employees" with four columns: EmployeeID, FirstName, LastName, and Salary. It then inserts three rows into the table. The SELECT statement with WHERE clause filters rows where Salary is greater than 60000.00. In this case, it will return the row with 'Alice' as the FirstName and 70000.00 as the Salary.
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Community Answer
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIM...
Output of the above code:
The output of the above code will be:
Alice, 70000.00
Explanation:
The provided SQL code performs the following actions:
1. It creates a table named "Orders" with four columns: OrderID, CustomerID, TotalAmount, and OrderDate. The primary key constraint is applied to the OrderID column.
2. It inserts three rows into the Orders table with the specified values for each column.
3. It selects the CustomerID and the sum of TotalAmount for each customer from the Orders table, grouping the results by CustomerID.
The output is "Alice, 70000.00" because the SUM() function calculates the total amount for each customer, and the GROUP BY clause groups the results by CustomerID. In this case, there is only one customer with ID 103 (Alice), and their total amount is 70000.00.
The other customers (CustomerID 101 and 102) have different total amounts (100.50 and 200.75, respectively), but they are not included in the output because they are not grouped by the CustomerID.
Therefore, the correct answer is option D) Alice, 70000.00.
The output of the above code will be:
Alice, 70000.00
Explanation:
The provided SQL code performs the following actions:
1. It creates a table named "Orders" with four columns: OrderID, CustomerID, TotalAmount, and OrderDate. The primary key constraint is applied to the OrderID column.
2. It inserts three rows into the Orders table with the specified values for each column.
3. It selects the CustomerID and the sum of TotalAmount for each customer from the Orders table, grouping the results by CustomerID.
The output is "Alice, 70000.00" because the SUM() function calculates the total amount for each customer, and the GROUP BY clause groups the results by CustomerID. In this case, there is only one customer with ID 103 (Alice), and their total amount is 70000.00.
The other customers (CustomerID 101 and 102) have different total amounts (100.50 and 200.75, respectively), but they are not included in the output because they are not grouped by the CustomerID.
Therefore, the correct answer is option D) Alice, 70000.00.
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Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer?
Question Description
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer?.
Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer?.
Solutions for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development.
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Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider the following SQL code:CREATE TABLE Orders ( OrderID INT PRIMARY KEY, CustomerID INT, TotalAmount DECIMAL(10, 2), OrderDate DATE);INSERT INTO Orders (OrderID, CustomerID, TotalAmount, OrderDate)VALUES (1, 101, 100.50, 2023-05-01), (2, 102, 200.75, 2023-05-02), (3, 103, 150.20, 2023-05-03);SELECT CustomerID, SUM(TotalAmount) FROM Orders GROUP BY CustomerID;What is the output of the above code?a)No outputb)Errorc)Jane, 60000.00 Alice, 70000.00d)Alice, 70000.00Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Software Development tests.
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