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What will be the output of the following code?
var x = 10;
var x = 10;
function test() {
if (x === 10) {
var x = 20;
}
if (x === 10) {
var x = 20;
}
console.log(x);
}
}
test();
- a)10
- b)undefined
- c)20
- d)Error
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code?var x = 10;function test...
The 'var x = 20' declaration inside the 'if' statement creates a new variable 'x' with block scope. Since the 'console.log(x)' statement is outside the block, it refers to the outer variable 'x', which is undefined.
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Community Answer
What will be the output of the following code?var x = 10;function test...
Explanation:
Variable Scope:
- In JavaScript, variables declared with the keyword `var` are function-scoped.
- The variable `x` declared inside the `test` function using `var` keyword is hoisted to the top of the function scope.
Code Execution:
1. The variable `x` is declared and assigned the value 10.
2. The `test` function is called.
3. Inside the `test` function, a new variable `x` is declared with the value 20. This new `x` variable is scoped only within the `if` block.
4. When we try to access `x` inside the `if` block, it refers to the local variable `x`, which is declared but not yet assigned a value. This results in `undefined`.
5. Therefore, the output of the code will be `undefined`.
Output:
- undefined
Variable Scope:
- In JavaScript, variables declared with the keyword `var` are function-scoped.
- The variable `x` declared inside the `test` function using `var` keyword is hoisted to the top of the function scope.
Code Execution:
1. The variable `x` is declared and assigned the value 10.
2. The `test` function is called.
3. Inside the `test` function, a new variable `x` is declared with the value 20. This new `x` variable is scoped only within the `if` block.
4. When we try to access `x` inside the `if` block, it refers to the local variable `x`, which is declared but not yet assigned a value. This results in `undefined`.
5. Therefore, the output of the code will be `undefined`.
Output:
- undefined
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