Software Development Exam  >  Software Development Questions  >  Consider the following table structure:CREATE... Start Learning for Free
Consider the following table structure:
CREATE TABLE Students (
  StudentID INT PRIMARY KEY,
  StudentName VARCHAR(50),
  CourseID INT,
  Grade VARCHAR(2)
);
Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?
  • a)
    SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;
  • b)
    SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;
  • c)
    SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;
  • d)
    SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Consider the following table structure:CREATE TABLE Students ( Student...
The SQL statement SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID; calculates the count of distinct StudentID values for each CourseID in the Students table, giving the number of students enrolled in each course along with the course ID.
View all questions of this test
Most Upvoted Answer
Consider the following table structure:CREATE TABLE Students ( Student...
The Correct Answer

The correct answer is option 'A': SELECT COUNT(*) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;

Explanation

The given table structure is for a Students table, which contains information about students such as their ID, name, course ID, and grade. The goal is to return the number of students enrolled in each course along with the course ID.

Let's analyze each option to understand why option 'A' is the correct answer.

a) SELECT COUNT(*) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;

This option uses the COUNT(*) function to count the number of rows in the Students table for each unique CourseID. The GROUP BY clause is used to group the results by CourseID. This query will return the total number of students enrolled in each course along with the corresponding CourseID.

b) SELECT COUNT(*) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;

This option is similar to option 'A', but it includes a condition in the WHERE clause to only count the students who have a non-null grade. However, the requirement is to count all students enrolled in each course, regardless of their grade. Therefore, this option is not correct.

c) SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;

This option uses the COUNT(DISTINCT StudentID) function to count the number of distinct StudentIDs for each unique CourseID. The DISTINCT keyword ensures that each StudentID is counted only once. However, this query does not consider the total number of students enrolled in each course. It only counts the number of distinct StudentIDs. Therefore, this option is not correct.

d) SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;

This option is similar to option 'C', but it includes a condition in the WHERE clause to only count the students who have a non-null grade. As mentioned earlier, the requirement is to count all students enrolled in each course, regardless of their grade. Therefore, this option is not correct.

Conclusion

Option 'A' is the correct answer because it retrieves the total number of students enrolled in each course by counting all the rows in the Students table for each unique CourseID using COUNT(*). The GROUP BY clause ensures that the results are grouped by CourseID.
Explore Courses for Software Development exam

Similar Software Development Doubts

Top Courses for Software Development

Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer?
Question Description
Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer?.
Solutions for Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development. Download more important topics, notes, lectures and mock test series for Software Development Exam by signing up for free.
Here you can find the meaning of Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Consider the following table structure:CREATE TABLE Students ( StudentID INT PRIMARY KEY, StudentName VARCHAR(50), CourseID INT, Grade VARCHAR(2));Which of the following SQL statements will return the number of students enrolled in each course along with the course ID?a)SELECT COUNT() AS TotalStudents, CourseID FROM Students GROUP BY CourseID;b)SELECT COUNT() AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;c)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students GROUP BY CourseID;d)SELECT COUNT(DISTINCT StudentID) AS TotalStudents, CourseID FROM Students WHERE Grade IS NOT NULL GROUP BY CourseID;Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Software Development tests.
Explore Courses for Software Development exam

Top Courses for Software Development

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev