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Find the cartesian equation of the plane which passes through the point (5, 2, -4) and perpendicular to the line with direction ratios 2, 3, -1?
  • a)
    x + 2y - 3z = 18
  • b)
    2x + 3y - z = 20
  • c)
    2x + 3y - 5y = 24
  • d)
    2x + 5y - 7z = 15
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the cartesian equation of the plane which passes through the poin...
Given:
The plane which passes through the point (5, 2, -4)
Plane is perpendicular to the line with direction ratios 2, 3, -1
Concept:
Cartesian equation of the plane passing through (x1 , y1 , z1) and perpendicular to line having drs a, b, c is given by :
a(x - x1) + b(y - y1) + c(z - z1) = 0
Solution:
Equation of plane :
2(x - 5) + 3(y - 2) -(z - (-4)) = 0
⇒ 2x + 3y - z = 20
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Find the cartesian equation of the plane which passes through the point (5, 2, -4) and perpendicular to the line with direction ratios 2, 3, -1?a)x + 2y - 3z = 18b)2x + 3y - z = 20c)2x + 3y - 5y = 24d)2x + 5y - 7z = 15Correct answer is option 'B'. Can you explain this answer?
Question Description
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