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A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth; R being the radius of the earth. What will be the time period of another satellite at a height 2.5R from the surface of the earth?
  • a)
    6√2h
  • b)
  • c)
    6√3 h
  • d)
    12 h
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A geostationary satellite is orbiting the earth at a height of 6Rabove...
According to Kepler's law of periods,
T∝ a3
where, a is the semi-major axis.Here, in case one,
a = R + 6R = 7R as satellite is 6R distance above the earth and for a geostationary satellite,
T = 24 h
∴ (24)∝ (7R)3......(i)
Similarly for case two,
T2 ∝ (3.5R)3......(ii)
Dividing equation (i) by equation (ii), we get,
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A geostationary satellite is orbiting the earth at a height of 6Rabove the surface of the earth; Rbeing the radius of the earth. What will be the time period of another satellite at a height 2.5Rfrom the surface of the earth?a)6√2hb)c)6√3 hd)12 hCorrect answer is option 'A'. Can you explain this answer?
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