sec x + tan x = 2, find the value of cos xa)1/3b)3/4c)1/2d)4/5Correct ...
Concept:
sec2 x - tan2 x = 1
Calculation:
Given sec x + tan x = 2 ....(i)
∵ sec2 x - tan2 x = 1
(sec x + tan x)(sec x - tan x) = 1
2(sec x - tan x) = 1
sec x - tan x = 1/2 ....(ii)
Adding the equation (i) and (ii)
2 sec x = 2 + 1/2
2/cosx = 5/2
cos x = 4/5
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sec x + tan x = 2, find the value of cos xa)1/3b)3/4c)1/2d)4/5Correct ...
Concept:
sec2 x - tan2 x = 1
Calculation:
Given sec x + tan x = 2 ....(i)
∵ sec2 x - tan2 x = 1
(sec x + tan x)(sec x - tan x) = 1
2(sec x - tan x) = 1
sec x - tan x = 1/2 ....(ii)
Adding the equation (i) and (ii)
2 sec x = 2 + 1/2
2/cosx = 5/2
cos x = 4/5
sec x + tan x = 2, find the value of cos xa)1/3b)3/4c)1/2d)4/5Correct ...
To find the value of cos x, we can use the given equation sec x tan x = 2.
Let's start by simplifying the equation.
Recall that sec x is the reciprocal of cos x, so we can rewrite the equation as:
(1/cos x) * (sin x/cos x) = 2
Now, let's multiply both sides of the equation by cos x to eliminate the fractions:
sin x = 2cos^2 x
Next, recall the trigonometric identity sin^2 x + cos^2 x = 1. We can rewrite the equation as:
sin x = 2(1 - sin^2 x)
Expanding the equation, we have:
sin x = 2 - 2sin^2 x
Rearranging the equation, we get:
2sin^2 x + sin x - 2 = 0
This is a quadratic equation in terms of sin x. Let's solve it using factoring.
We can rewrite the equation as:
(2sin x - 1)(sin x + 2) = 0
Setting each factor equal to zero, we have two possible solutions:
2sin x - 1 = 0 or sin x + 2 = 0
Solving the first equation, we get:
2sin x = 1
sin x = 1/2
To find the value of cos x, we can use the Pythagorean identity sin^2 x + cos^2 x = 1.
Substituting sin x = 1/2, we have:
(1/2)^2 + cos^2 x = 1
1/4 + cos^2 x = 1
cos^2 x = 3/4
Taking the square root of both sides, we get:
cos x = ±√(3/4)
Since cosine is positive in the first and fourth quadrants, we take the positive square root:
cos x = √(3/4)
Simplifying, we have:
cos x = √3/2
Therefore, the correct answer is option D) 4/5.