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Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared
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the Software Development exam syllabus. Information about Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development.
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Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider the following SQL query:SELECT e.employee_name, d.department_nameFROM employees eJOIN departments d ON e.department_id = d.department_idWHERE e.salary > (SELECT AVG(salary) FROM employees)ORDER BY e.employee_name;What does the above query return?a)Names of employees in the departments with the highest average salaryb)Names of employees with a salary higher than the average salaryc)Names of employees and their corresponding department namesd)Names of employees in the departments with the lowest average salaryCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Software Development tests.