Consider the following table structure:Table: EmployeesColumns: Employ...
Answer:Explanation:
To find the total number of employees in each department, we need to use the
COUNT() function along with the
GROUP BY clause. The
GROUP BY clause is used to group the rows based on a specific column, in this case, the DepartmentID.
Let's analyze each query option to understand why option 'A' is the correct answer:
Option 'A': SELECT DepartmentID, COUNT(*) FROM Employees GROUP BY DepartmentID;
This query selects the DepartmentID column and counts the number of rows for each DepartmentID using the
COUNT(*) function. The result is grouped by DepartmentID using the
GROUP BY clause. This will give us the total number of employees in each department.
Advantages:- This query is specifically designed to calculate the total number of employees in each department.
- It uses the correct aggregation function
COUNT() to count the number of rows.
Disadvantages:- None.
Option 'B': SELECT DepartmentID, SUM(EmployeeID) FROM Employees GROUP BY DepartmentID;
This query selects the DepartmentID column and sums up the EmployeeID column for each DepartmentID using the
SUM() function. The result is grouped by DepartmentID using the
GROUP BY clause. However, this query does not give us the total number of employees in each department, as it sums up the EmployeeID values instead.
Advantages:- None.
Disadvantages:- This query does not give us the total number of employees in each department.
Option 'C': SELECT DepartmentID, AVG(EmployeeID) FROM Employees GROUP BY DepartmentID;
This query selects the DepartmentID column and calculates the average of the EmployeeID values for each DepartmentID using the
AVG() function. The result is grouped by DepartmentID using the
GROUP BY clause. However, this query does not give us the total number of employees in each department, as it calculates the average of the EmployeeID values instead.
Advantages:- None.
Disadvantages:- This query does not give us the total number of employees in each department.
Option 'D': SELECT DepartmentID, MAX(EmployeeID) FROM Employees GROUP BY DepartmentID;
This query selects the DepartmentID column and finds the maximum value of the EmployeeID column for each DepartmentID using the
MAX() function. The result is grouped by DepartmentID using the
GROUP BY clause. However, this query does not give us the total number of employees in each department, as it finds the maximum EmployeeID value instead.
Advantages:- None.
Disadvantages:- This query does not give us the total number of employees in each department.
Therefore, the correct answer is option 'A' as it correctly uses the
COUNT() function and the
GROUP BY clause to return the total number of employees in each department.