Introduction:
The area of a parallelogram is defined as the space enclosed by the four sides of the parallelogram. In this article, we will discuss the procedure to show that the area of parallelogram is the product of its base and height.

Procedure:
To prove that the area of parallelogram is the product of its base and height, we need to follow the below steps:

1. Draw a parallelogram:
Draw a parallelogram with two parallel sides and two non-parallel sides. Label the parallel sides as AB and CD and the non-parallel sides as AD and BC.

2. Draw a perpendicular line:
Draw a perpendicular line from the base AB to the opposite side CD. Label the point of intersection as E.

3. Draw height:
Draw a line segment from vertex A perpendicular to the base CD. Label the point of intersection as F.

4. Calculate area:
The area of the parallelogram is given by the formula: Area = Base × Height. In this case, the base is AB and the height is AF. Therefore, the area of the parallelogram is AB × AF.

5. Prove the formula:
To prove the formula, we need to show that the area of the parallelogram is equal to AB × AF. We can do this by showing that the triangle AEF is congruent to the triangle CEF. Since the two triangles are congruent, they have the same area. The area of triangle AEF is 1/2 × AB × AF and the area of triangle CEF is 1/2 × CD × EF. Therefore, we can write:

1/2 × AB × AF = 1/2 × CD × EF

Multiplying both sides by 2, we get:

AB × AF = CD × EF

Since EF is the height of the parallelogram, we can substitute it in the above equation to get:

Area of parallelogram = AB × Height

Conclusion:
Thus, we have proved that the area of parallelogram is the product of its base and height. This formula is useful in solving problems related to the area of parallelograms in geometry.