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In ΔABC. ∠A + ∠B = 145° and ∠C + 2∠B = 180°. State which one of the following relations is true? (SSC Sub. Ins. 2013)
  • a)
    CA = AB
  • b)
    CA < AB
  • c)
    BC < AB
  • d)
    CA > AB
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In ΔABC. ∠A + ∠B = 145° and ∠C + 2∠B = 180&d...

∠A + ∠B = 145°
∠C + 180° – 145° = 35°
∠C + 2∠B = 180°
⇒ 2∠B = 180° – 35° = 145°
⇒ ∠B = 145/2 = 72.5 ° = ∠A
∠B > ∠C
∴ CA > AB
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Community Answer
In ΔABC. ∠A + ∠B = 145° and ∠C + 2∠B = 180&d...
Given Information:
- ∠A + ∠B = 145°
- ∠C + 2∠B = 180°

Explanation:
To find the relation between the sides of the triangle, let's use the angle sum property of a triangle. The sum of the three angles in a triangle is always 180°.

Angle Sum Property:
- ∠A + ∠B + ∠C = 180°

Substitute the given angles:
- (145°) + ∠C = 180°
- ∠C = 180° - 145°
- ∠C = 35°
Now, let's use the given information to find the relation between the sides of the triangle.

Relation Between Sides:
- From the angle sum property, we know that ∠A + ∠B + ∠C = 180°.
- Substituting the given angles, we get: 145° + ∠B + 35° = 180°.
- ∠B = 180° - 145° - 35° = 0°.
Since ∠B = 0°, this implies that side CA is opposite the angle with measure 0°, which means side CA is the longest side in the triangle.
Therefore, the correct relation is:

CA > AB
So, the correct answer is option 'D'.
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