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If 40 GMs. are inserted between 2 and 40 then product of 10th GM from beginning and that of from end is (a) 20 (b) 40 (c) 80 (d) None?
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If 40 GMs. are inserted between 2 and 40 then product of 10th GM from ...
Solution:

Given, 40 GMs are inserted between 2 and 40.

Let the first GM be a and the common difference be d.

Then, the 40th GM is given by a+39d = 40

Also, the sum of the terms is given by [n/2] [2a + (n-1)d] = 38

Solving the above two equations, we get a = 3/2 and d = 1/2

Therefore, the 10th GM from the beginning is given by a+9d = 8 and the 10th GM from the end is given by a+31d = 18

Hence, the product of the 10th GM from beginning and that of from end is 8×18 = 144.

Therefore, the correct option is (d) None.
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If 40 GMs. are inserted between 2 and 40 then product of 10th GM from beginning and that of from end is (a) 20 (b) 40 (c) 80 (d) None?
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If 40 GMs. are inserted between 2 and 40 then product of 10th GM from beginning and that of from end is (a) 20 (b) 40 (c) 80 (d) None? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If 40 GMs. are inserted between 2 and 40 then product of 10th GM from beginning and that of from end is (a) 20 (b) 40 (c) 80 (d) None? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 40 GMs. are inserted between 2 and 40 then product of 10th GM from beginning and that of from end is (a) 20 (b) 40 (c) 80 (d) None?.
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