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The graph of the polynomial 2x- 8x + 5 cuts the y-axis at __________
  • a)
    (6, 0)
  • b)
    (0, 7)
  • c)
    (0, 5)
  • d)
    (8, 9)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at __________a...
The graph of the polynomial 2x- 8x + 5 cuts the y-axis.
Hence, the value of x will be 0.
y(0) = 2(0)- 8(0) + 5
y = 5
The graph cuts the y-axis at (0, 5)
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Most Upvoted Answer
The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at __________a...
The graph of the polynomial 2x- 8x + 5 cuts the y-axis.
Hence, the value of x will be 0.
y(0) = 2(0)- 8(0) + 5
y = 5
The graph cuts the y-axis at (0, 5)
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Community Answer
The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at __________a...
To find the y-intercept of a polynomial, we need to substitute x=0 into the polynomial equation and solve for y.

Given polynomial: 2x^2 - 8x + 5

1. Substituting x=0 into the equation:
y = 2(0)^2 - 8(0) + 5
y = 0 - 0 + 5
y = 5

Therefore, the y-intercept is (0, 5), which corresponds to option C.

Explanation:
The y-intercept is the point at which the graph of a function intersects the y-axis. It is the point where the x-coordinate is 0. In this case, we substitute x=0 into the polynomial equation to find the corresponding y-coordinate.

Steps:
1. Substitute x=0 into the polynomial equation.
2. Simplify the equation by performing the necessary calculations.
3. The resulting value is the y-coordinate of the y-intercept.
4. Write the y-intercept in the form (0, y-coordinate).

In this case, when we substitute x=0 into the polynomial equation 2x^2 - 8x + 5, we get y=5. Therefore, the y-intercept is (0, 5).
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The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at __________a)(6, 0)b)(0, 7)c)(0, 5)d)(8, 9)Correct answer is option 'C'. Can you explain this answer?
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