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ax+ bx + c ≥ 0 is a strict inequality.
  • a)
    True
  • b)
    False
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
ax2+ bx + c ≥ 0 is a strict inequality.a)Trueb)FalseCorrect answer ...
Since it has equality sign along with inequality sign so it is a slack inequality not strict inequality.
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Community Answer
ax2+ bx + c ≥ 0 is a strict inequality.a)Trueb)FalseCorrect answer ...
The given expression is ax^2 + bx + c.
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ax2+ bx + c ≥ 0 is a strict inequality.a)Trueb)FalseCorrect answer is option 'A'. Can you explain this answer?
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