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def hash_function(key):
    return key % 5
hash_table = [[] for _ in range(5)]
keys = [15, 7, 22, 3, 12]
for key in keys:
    index = hash_function(key)
    hash_table[index].append(key)
print(hash_table)
What will be the output of the above code?
  • a)
    [[], [], [3], [], [7, 12, 22, 15]]
  • b)
    [[], [3, 12], [22], [7], [15]]
  • c)
    [[], [7], [22], [3], [12, 15]]
  • d)
    [[], [15, 7, 22, 3, 12], [], [], []]
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
def hash_function(key): return key % 5hash_table = [[] for _ in range...
The code demonstrates hash table implementation using a hash function that performs modulo division. Each key from the keys list is hashed, and the resulting index is used to append the key to the corresponding bucket in the hash_table.
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def hash_function(key): return key % 5hash_table = [[] for _ in range(5)]keys = [15, 7, 22, 3, 12]for key in keys: index = hash_function(key) hash_table[index].append(key)print(hash_table)What will be the output of the above code?a)[[], [], [3], [], [7, 12, 22, 15]]b)[[], [3, 12], [22], [7], [15]]c)[[], [7], [22], [3], [12, 15]]d)[[], [15, 7, 22, 3, 12], [], [], []]Correct answer is option 'A'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about def hash_function(key): return key % 5hash_table = [[] for _ in range(5)]keys = [15, 7, 22, 3, 12]for key in keys: index = hash_function(key) hash_table[index].append(key)print(hash_table)What will be the output of the above code?a)[[], [], [3], [], [7, 12, 22, 15]]b)[[], [3, 12], [22], [7], [15]]c)[[], [7], [22], [3], [12, 15]]d)[[], [15, 7, 22, 3, 12], [], [], []]Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for def hash_function(key): return key % 5hash_table = [[] for _ in range(5)]keys = [15, 7, 22, 3, 12]for key in keys: index = hash_function(key) hash_table[index].append(key)print(hash_table)What will be the output of the above code?a)[[], [], [3], [], [7, 12, 22, 15]]b)[[], [3, 12], [22], [7], [15]]c)[[], [7], [22], [3], [12, 15]]d)[[], [15, 7, 22, 3, 12], [], [], []]Correct answer is option 'A'. Can you explain this answer?.
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