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(ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)
- a)-1238.78 J mol-1
- b)1238.78 L mol-1
- c)-2477.58 J mol-1
- d)2477.58 J mol-1
Correct answer is option 'B'. Can you explain this answer?
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Calculation of ΔH - ΔU for the formation of carbon monoxide (CO)
The enthalpy change (ΔH) for the formation of carbon monoxide from its elements can be calculated using the standard enthalpies of formation for carbon monoxide (ΔHf CO), carbon (ΔHf C), and oxygen (ΔHf O2).
Standard enthalpy change for the reaction:
ΔH = ΣΔHf(products) - ΣΔHf(reactants)
Given:
ΔHf CO = -110.5 kJ/mol
ΔHf C = 0 kJ/mol
ΔHf O2 = 0 kJ/mol
Therefore, ΔH = ΔHf CO - (ΔHf C + 0.5ΔHf O2)
ΔH = -110.5 kJ/mol - (0 + 0)
ΔH = -110.5 kJ/mol
Calculation of ΔU:
ΔU = ΔH - ΔnRT
where,
Δn = (sum of moles of products) - (sum of moles of reactants)
Δn = 1 - (1 + 0.5) = 0.5 moles
Given:
R = 8.314 kJ/mol-K
T = 298 K
ΔU = -110.5 kJ/mol - (0.5 mol)(8.314 kJ/mol-K)(298 K)
ΔU = -110.5 kJ/mol - 1238.78 kJ/mol
ΔU = -1349.28 kJ/mol
ΔH - ΔU:
ΔH - ΔU = (-110.5 kJ/mol) - (-1349.28 kJ/mol)
ΔH - ΔU = 1238.78 kJ/mol
Therefore, the correct answer is option B) 1238.78 kJ/mol.
The enthalpy change (ΔH) for the formation of carbon monoxide from its elements can be calculated using the standard enthalpies of formation for carbon monoxide (ΔHf CO), carbon (ΔHf C), and oxygen (ΔHf O2).
Standard enthalpy change for the reaction:
ΔH = ΣΔHf(products) - ΣΔHf(reactants)
Given:
ΔHf CO = -110.5 kJ/mol
ΔHf C = 0 kJ/mol
ΔHf O2 = 0 kJ/mol
Therefore, ΔH = ΔHf CO - (ΔHf C + 0.5ΔHf O2)
ΔH = -110.5 kJ/mol - (0 + 0)
ΔH = -110.5 kJ/mol
Calculation of ΔU:
ΔU = ΔH - ΔnRT
where,
Δn = (sum of moles of products) - (sum of moles of reactants)
Δn = 1 - (1 + 0.5) = 0.5 moles
Given:
R = 8.314 kJ/mol-K
T = 298 K
ΔU = -110.5 kJ/mol - (0.5 mol)(8.314 kJ/mol-K)(298 K)
ΔU = -110.5 kJ/mol - 1238.78 kJ/mol
ΔU = -1349.28 kJ/mol
ΔH - ΔU:
ΔH - ΔU = (-110.5 kJ/mol) - (-1349.28 kJ/mol)
ΔH - ΔU = 1238.78 kJ/mol
Therefore, the correct answer is option B) 1238.78 kJ/mol.
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(ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer?.
(ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer?.
Solutions for (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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(ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of (ΔH - ΔU) for formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 KJ-1 mol-1)a)-1238.78 J mol-1b)1238.78 L mol-1c)-2477.58 J mol-1d)2477.58 J mol-1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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