Software Development Exam > Software Development Questions > Given a stack st with elements [1, 2, 3, 4, 5...
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Given a stack st with elements [1, 2, 3, 4, 5], what will be the output of the following code?
#include <iostream>
#include <stack>
using namespace std;
#include <iostream>
#include <stack>
using namespace std;
void display(stack<int>& st) {
while (!st.empty()) {
cout << st.top() << " ";
st.pop();
}
}
while (!st.empty()) {
cout << st.top() << " ";
st.pop();
}
}
int main() {
stack<int> st;
st.push(1);
st.push(2);
st.push(3);
display(st);
return 0;
}
stack<int> st;
st.push(1);
st.push(2);
st.push(3);
display(st);
return 0;
}
- a)1 2 3
- b)3 2 1
- c)Compile-time error
- d)Run-time error
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Given a stack st with elements [1, 2, 3, 4, 5], what will be the outpu...
The display() function pops elements from the stack and prints them until the stack becomes empty. The elements are printed in the reverse order of their insertion, resulting in "3 2 1".
Most Upvoted Answer
Given a stack st with elements [1, 2, 3, 4, 5], what will be the outpu...
Understanding the Code
The provided C++ code manipulates a stack and displays its contents. Let's break down the key components.
Stack Initialization
- A stack of integers is created.
- Elements 1, 2, and 3 are pushed onto the stack in that order.
Function Definition
- The `display` function takes a stack by reference.
- It uses a `while` loop to print the top element and then pops it from the stack until the stack is empty.
Function Execution
- When calling `display(st)` in `main()`, the stack contains only the elements 1, 2, and 3.
- The `display` function will print the top element (3), then pop it.
- This process continues, printing 2 next, then popping it, and finally printing 1.
Result of the Code
- The output sequence will be 3, 2, 1 since the stack is a Last In, First Out (LIFO) structure.
Final Output
- Therefore, the correct answer is option 'B': 3 2 1.
In summary, the stack's behavior leads to the last elements pushed being the first ones to be displayed, resulting in the output being reversed from their original insertion order.
The provided C++ code manipulates a stack and displays its contents. Let's break down the key components.
Stack Initialization
- A stack of integers is created.
- Elements 1, 2, and 3 are pushed onto the stack in that order.
Function Definition
- The `display` function takes a stack by reference.
- It uses a `while` loop to print the top element and then pops it from the stack until the stack is empty.
Function Execution
- When calling `display(st)` in `main()`, the stack contains only the elements 1, 2, and 3.
- The `display` function will print the top element (3), then pop it.
- This process continues, printing 2 next, then popping it, and finally printing 1.
Result of the Code
- The output sequence will be 3, 2, 1 since the stack is a Last In, First Out (LIFO) structure.
Final Output
- Therefore, the correct answer is option 'B': 3 2 1.
In summary, the stack's behavior leads to the last elements pushed being the first ones to be displayed, resulting in the output being reversed from their original insertion order.
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