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Given a queue q with elements [1, 2, 3, 4, 5], what will be the output of the following code?
#include <iostream>
#include <queue>
using namespace std;
void display(queue<int>& q) {
   while (!q.empty()) {
       cout << q.front() << " ";
       q.pop();
   }
}
int main() {
   queue<int> q;
   q.push(1);
   q.push(2);
   q.push(3);
   display(q);
   return 0;
}
  • a)
    1 2 3
  • b)
    3 2 1
  • c)
    Compile-time error
  • d)
    Run-time error
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Given a queue q with elements [1, 2, 3, 4, 5], what will be the output...
The display() function dequeues elements from the queue and prints them until the queue becomes empty. The elements are printed in the order of their insertion, resulting in "1 2 3".
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Given a queue q with elements [1, 2, 3, 4, 5], what will be the output of the following code?#include <iostream>#include <queue>using namespace std;void display(queue<int>& q) { while (!q.empty()) { cout << q.front() << " "; q.pop(); }}int main() { queue<int> q; q.push(1); q.push(2); q.push(3); display(q); return 0;}a)1 2 3b)3 2 1c)Compile-time errord)Run-time errorCorrect answer is option 'A'. Can you explain this answer?
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