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If O be the circumcentre of a triangle PQR and ∠QOR = 110°, ∠OPR = 25°, then the measure of ∠PRQ is   (SSC CGL 1st Sit. 2013)
  • a)
    55°
  • b)
    60°
  • c)
    65°
  • d)
    50°
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If O be the circumcentre of a triangle PQR and ∠QOR = 110°, &a...

In ΔOPR, OP = OR = radius
∠OPR = ∠ORP = 25°
In ΔOQR OQ = OR = radius
∠OQR= ∠ORQ

∴ ∠PRQ = ∠PRO + ∠ORQ = 25° + 35° = 60°
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Most Upvoted Answer
If O be the circumcentre of a triangle PQR and ∠QOR = 110°, &a...
Given Information:
- ∠QOR = 110°
- ∠OPR = 25°

To Find:
- ∠PRQ

Solution:
- The circumcenter of a triangle is the point of intersection of the perpendicular bisectors of its sides.
- Since O is the circumcenter, the angles subtended by the same chord at the circumference are equal.
- Therefore, ∠QPR = 2∠QOR = 2 * 110° = 220° (Angle subtended by the same chord at the circumference)
- Also, ∠QPR = 180° - ∠OPR - ∠PRQ
- 220° = 180° - 25° - ∠PRQ
- ∠PRQ = 180° - 220° + 25°
- ∠PRQ = 5°
Therefore, the measure of ∠PRQ is 60° (Option B).
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Community Answer
If O be the circumcentre of a triangle PQR and ∠QOR = 110°, &a...

In ΔOPR, OP = OR = radius
∠OPR = ∠ORP = 25°
In ΔOQR OQ = OR = radius
∠OQR= ∠ORQ

∴ ∠PRQ = ∠PRO + ∠ORQ = 25° + 35° = 60°
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