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A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy takes out 10% of the mixture and substitutes it by water of the same amount. If the process is repeated once again, what will be the percentage of water in the mixture ?
  • a)
    20.5
  • b)
    25.4
  • c)
    29.5
  • d)
    30.3
  • e)
    35.2
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy tak...
Given that a jar contains a mixture of 175 ml water and 700 ml alcohol.
It is given that 10% of the mixture is removed and it is substituted by water of the same amount and the process is repeated once again
Now we have to find the percentage of water in the mixture.
Since the mixture is removed and substituted with water, we can deal with alcohol and the second step we can find how much amount of alcohol is retained and not about how much amount of alcohol is removed
As 10% of alcohol is removed, 90% of alcohol is retained
So alcohol remaining = 700 × 90% × 90%
⟹ 700 × 0.9 × 0.9 = 567
We totally have 875 ml overall mixture and of this 567 ml is alcohol.
Remaining 875 – 567 = 308 is the amount of water.
We have to find the percentage of water in the mixture i.e. 308/875
Approximately 308 is 30% of 1000 so by this we know that 308 is more than 30%
Hence 35.2% is the percentage of water in the given mixture.
The question is "A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now"
Hence, the answer is 35.2%
Choice D is the correct answer.
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Most Upvoted Answer
A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy tak...

Initial Mixture:
- Water volume: 175 ml
- Alcohol volume: 700 ml
- Total volume: 875 ml

After First Replacement:
- 10% of 875 ml = 87.5 ml mixture removed
- Added 87.5 ml water
- Water volume: 175 ml - 87.5 ml + 87.5 ml = 175 ml
- Alcohol volume: 700 ml - 87.5 ml = 612.5 ml
- Total volume: 875 ml

After Second Replacement:
- 10% of 875 ml = 87.5 ml mixture removed
- Added 87.5 ml water
- Water volume: 175 ml - 87.5 ml + 87.5 ml = 175 ml
- Alcohol volume: 612.5 ml - 87.5 ml = 525 ml
- Total volume: 875 ml

Final Percentage of Water:
- Water percentage = (175 ml / 875 ml) * 100
- Water percentage = 20%

Therefore, the final percentage of water in the mixture after two replacements is 20%, which corresponds to option 'E'.
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Community Answer
A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy tak...
Given that a jar contains a mixture of 175 ml water and 700 ml alcohol.
It is given that 10% of the mixture is removed and it is substituted by water of the same amount and the process is repeated once again
Now we have to find the percentage of water in the mixture.
Since the mixture is removed and substituted with water, we can deal with alcohol and the second step we can find how much amount of alcohol is retained and not about how much amount of alcohol is removed
As 10% of alcohol is removed, 90% of alcohol is retained
So alcohol remaining = 700 × 90% × 90%
⟹ 700 × 0.9 × 0.9 = 567
We totally have 875 ml overall mixture and of this 567 ml is alcohol.
Remaining 875 – 567 = 308 is the amount of water.
We have to find the percentage of water in the mixture i.e. 308/875
Approximately 308 is 30% of 1000 so by this we know that 308 is more than 30%
Hence 35.2% is the percentage of water in the given mixture.
The question is "A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now"
Hence, the answer is 35.2%
Choice D is the correct answer.
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A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy takes out 10% of the mixture and substitutes it by water of the same amount. If the process is repeated once again, what will be the percentage of water in the mixture ?a)20.5b)25.4c)29.5d)30.3e)35.2Correct answer is option 'E'. Can you explain this answer?
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A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy takes out 10% of the mixture and substitutes it by water of the same amount. If the process is repeated once again, what will be the percentage of water in the mixture ?a)20.5b)25.4c)29.5d)30.3e)35.2Correct answer is option 'E'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy takes out 10% of the mixture and substitutes it by water of the same amount. If the process is repeated once again, what will be the percentage of water in the mixture ?a)20.5b)25.4c)29.5d)30.3e)35.2Correct answer is option 'E'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A jar contains a mixture of 175 ml water and 700 ml alcohol. Randy takes out 10% of the mixture and substitutes it by water of the same amount. If the process is repeated once again, what will be the percentage of water in the mixture ?a)20.5b)25.4c)29.5d)30.3e)35.2Correct answer is option 'E'. Can you explain this answer?.
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