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A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?
- a)22.22%
- b)33.33%
- c)38.75%
- d)44.44%
- e)58.33%
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A beaker was filled with a mixture of 40 liters of water and a liquid ...
Given a mixture of 40 liters consisting of water and a chemical in a ratio of 3:5, we can calculate the percentage of the original amount of mixture that evaporated during a 10-day period.
First, we solve for the individual amounts of water and chemical in the mixture using the given ratio:
Let x represent the common multiplier.
Water = 3x
Chemical = 5x
Let x represent the common multiplier.
Water = 3x
Chemical = 5x
Solving the equation 3x + 5x = 40, we find x = 5.
Substituting x = 5, we find:
Water = 3 * 5 = 15 liters
Chemical = 5 * 5 = 25 liters
Water = 3 * 5 = 15 liters
Chemical = 5 * 5 = 25 liters
Over the 10-day period, water evaporates 2% each day, resulting in a total water loss of 10 * 2% = 20%.
Chemical evaporates 5% each day, resulting in a total chemical loss of 10 * 5% = 50%.
Chemical evaporates 5% each day, resulting in a total chemical loss of 10 * 5% = 50%.
Calculating the actual amount evaporated:
Water evaporated = 15 liters * 20% = 3 liters
Chemical evaporated = 25 liters * 50% = 12.5 liters
Water evaporated = 15 liters * 20% = 3 liters
Chemical evaporated = 25 liters * 50% = 12.5 liters
The total amount evaporated is the sum of water and chemical evaporated:
Total evaporated = 3 liters + 12.5 liters = 15.5 liters
Total evaporated = 3 liters + 12.5 liters = 15.5 liters
Finally, we calculate the percentage of the original mixture evaporated:
Percentage evaporated = (Total evaporated / Mixture total) * 100
Percentage evaporated = (15.5 liters / 40 liters) * 100 ≈ 38.75%
Percentage evaporated = (Total evaporated / Mixture total) * 100
Percentage evaporated = (15.5 liters / 40 liters) * 100 ≈ 38.75%
Therefore, the answer is C: 38.75%.
Most Upvoted Answer
A beaker was filled with a mixture of 40 liters of water and a liquid ...
Given a mixture of 40 liters consisting of water and a chemical in a ratio of 3:5, we can calculate the percentage of the original amount of mixture that evaporated during a 10-day period.
First, we solve for the individual amounts of water and chemical in the mixture using the given ratio:
Let x represent the common multiplier.
Water = 3x
Chemical = 5x
Let x represent the common multiplier.
Water = 3x
Chemical = 5x
Solving the equation 3x + 5x = 40, we find x = 5.
Substituting x = 5, we find:
Water = 3 * 5 = 15 liters
Chemical = 5 * 5 = 25 liters
Water = 3 * 5 = 15 liters
Chemical = 5 * 5 = 25 liters
Over the 10-day period, water evaporates 2% each day, resulting in a total water loss of 10 * 2% = 20%.
Chemical evaporates 5% each day, resulting in a total chemical loss of 10 * 5% = 50%.
Chemical evaporates 5% each day, resulting in a total chemical loss of 10 * 5% = 50%.
Calculating the actual amount evaporated:
Water evaporated = 15 liters * 20% = 3 liters
Chemical evaporated = 25 liters * 50% = 12.5 liters
Water evaporated = 15 liters * 20% = 3 liters
Chemical evaporated = 25 liters * 50% = 12.5 liters
The total amount evaporated is the sum of water and chemical evaporated:
Total evaporated = 3 liters + 12.5 liters = 15.5 liters
Total evaporated = 3 liters + 12.5 liters = 15.5 liters
Finally, we calculate the percentage of the original mixture evaporated:
Percentage evaporated = (Total evaporated / Mixture total) * 100
Percentage evaporated = (15.5 liters / 40 liters) * 100 ≈ 38.75%
Percentage evaporated = (Total evaporated / Mixture total) * 100
Percentage evaporated = (15.5 liters / 40 liters) * 100 ≈ 38.75%
Therefore, the answer is C: 38.75%.
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A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer?
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A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer?.
A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker was filled with a mixture of 40 liters of water and a liquid chemical. They are fixed in the ratio of 3 : 5, respectively. If 2 percent of the initial quantity of water and 5 percent of the initial quantity of liquid chemical evaporated each day during a 10-day period, what percent of the original amount of mixture evaporated during this period?a)22.22%b)33.33%c)38.75%d)44.44%e)58.33%Correct answer is option 'C'. Can you explain this answer?.
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