If |3 – x| < x + 5, which of the following may be true about ...
We have the inequality |3 - x| < x + 5.
To simplify this inequality, we consider two cases:
Case 1: (3 - x) is positive or zero:
In this case, the absolute value |3 - x| can be simplified to (3 - x). Therefore, our inequality becomes (3 - x) < x + 5.
Expanding the inequality, we have:
3 - x < x + 5
Adding x to both sides, we get:
3 < 2x + 5
Subtracting 5 from both sides, we have:
-2 < 2x
Dividing both sides by 2, we obtain:
-1 < x
So, in this case, the statement I. x > -1 is not true. Therefore, option C: I and II only cannot be correct.
Case 2: (3 - x) is negative:
In this case, the absolute value |3 - x| can be simplified to -(3 - x), changing the direction of the inequality. Therefore, our inequality becomes -(3 - x) < x + 5.
Expanding the inequality and simplifying, we have:
-x + 3 < x + 5
Adding x to both sides, we get:
3 < 2x + 5
Subtracting 5 from both sides, we have:
-2 < 2x
Dividing both sides by 2, we obtain:
-1 < x
So, in this case, the statement I. x > -1 is not true. Therefore, option C: I and II only cannot be correct.