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An unbiased coin is tossed 3 times, if the third toss gets head what is the probability of getting at least one more head?
- a)3/4
- b)1/4
- c)1/2
- d)1/3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An unbiased coin is tossed 3 times, if the third toss gets head what i...
Concept:
- The number of ways for selecting r from a group of n (n > r) = nCr
- The probability of particular case = Number of ways for the case can be executed/Total number of ways for selection
Calculation:
If it is known that third toss gets head, the possible cases:
(H, H, H), (H, T, H), (T, H, H), (T, T, H)
∴ Total cases possible = 4
Total favourable cases = 3 [(H, H, H), (H, T, H), (T, H, H)]
So, required probability P = Total favorable cases/Total possible cases
P = 3/4
Most Upvoted Answer
An unbiased coin is tossed 3 times, if the third toss gets head what i...
Understanding the Problem:
An unbiased coin is tossed 3 times, and we are given that the third toss resulted in a head. We need to find the probability of getting at least one more head in the remaining two tosses.
Solution:
To solve this problem, we can consider the possible outcomes of the first two tosses:
1. If the first two tosses result in two tails, the third toss must be a head to satisfy the given condition.
2. If the first two tosses result in one head and one tail, the third toss can be either a head or a tail.
3. If the first two tosses result in two heads, the third toss can be either a head or a tail.
Calculating the Probability:
- The probability of getting two tails in the first two tosses: 1/2 * 1/2 = 1/4
- The probability of getting one head and one tail in the first two tosses: 2 * (1/2 * 1/2) = 1/2
- The probability of getting two heads in the first two tosses: 1/2 * 1/2 = 1/4
Therefore, the total probability of getting at least one more head after the third toss is 1/4 + 1/2 + 1/4 = 3/4.
Therefore, the answer is option 'A' (3/4).
An unbiased coin is tossed 3 times, and we are given that the third toss resulted in a head. We need to find the probability of getting at least one more head in the remaining two tosses.
Solution:
To solve this problem, we can consider the possible outcomes of the first two tosses:
1. If the first two tosses result in two tails, the third toss must be a head to satisfy the given condition.
2. If the first two tosses result in one head and one tail, the third toss can be either a head or a tail.
3. If the first two tosses result in two heads, the third toss can be either a head or a tail.
Calculating the Probability:
- The probability of getting two tails in the first two tosses: 1/2 * 1/2 = 1/4
- The probability of getting one head and one tail in the first two tosses: 2 * (1/2 * 1/2) = 1/2
- The probability of getting two heads in the first two tosses: 1/2 * 1/2 = 1/4
Therefore, the total probability of getting at least one more head after the third toss is 1/4 + 1/2 + 1/4 = 3/4.
Therefore, the answer is option 'A' (3/4).
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Community Answer
An unbiased coin is tossed 3 times, if the third toss gets head what i...
Concept:
- The number of ways for selecting r from a group of n (n > r) = nCr
- The probability of particular case = Number of ways for the case can be executed/Total number of ways for selection
Calculation:
If it is known that third toss gets head, the possible cases:
(H, H, H), (H, T, H), (T, H, H), (T, T, H)
∴ Total cases possible = 4
Total favourable cases = 3 [(H, H, H), (H, T, H), (T, H, H)]
So, required probability P = Total favorable cases/Total possible cases
P = 3/4
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An unbiased coin is tossed 3 times, if the third toss gets head what is the probability of getting at least one more head?a)3/4b)1/4c)1/2d)1/3Correct answer is option 'A'. Can you explain this answer?
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