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If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, then
  • a)
    B ⊂ A
  • b)
    B = ϕ
  • c)
    A ⊂ B
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, then...
Concept:
  • P(A|B) = P(A∩B)/P(B)
  • P(B|A) = P(A∩B)/P(A)
  • A ⊂ B = Proper Subset: every element of A is in B, but B has more elements.
  • ϕ = Empty set = {}
Calculation:
Given: P(B/A) = 1
⇒ P(B|A) = P(A∩B)/P(A) = 1
⇒ P(A ∩ B) = P(A)
⇒ (A ∩ B) = A
So, every element of A is in B, but B has more elements.
∴ A ⊂ B
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Most Upvoted Answer
If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, then...
Concept:
  • P(A|B) = P(A∩B)/P(B)
  • P(B|A) = P(A∩B)/P(A)
  • A ⊂ B = Proper Subset: every element of A is in B, but B has more elements.
  • ϕ = Empty set = {}
Calculation:
Given: P(B/A) = 1
⇒ P(B|A) = P(A∩B)/P(A) = 1
⇒ P(A ∩ B) = P(A)
⇒ (A ∩ B) = A
So, every element of A is in B, but B has more elements.
∴ A ⊂ B
Free Test
Community Answer
If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, then...
Concept:
  • P(A|B) = P(A∩B)/P(B)
  • P(B|A) = P(A∩B)/P(A)
  • A ⊂ B = Proper Subset: every element of A is in B, but B has more elements.
  • ϕ = Empty set = {}
Calculation:
Given: P(B/A) = 1
⇒ P(B|A) = P(A∩B)/P(A) = 1
⇒ P(A ∩ B) = P(A)
⇒ (A ∩ B) = A
So, every element of A is in B, but B has more elements.
∴ A ⊂ B
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If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, thena)B ⊂ Ab)B = c)A ⊂ Bd)None of theseCorrect answer is option 'C'. Can you explain this answer?
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