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Ajay rolled two dice together. What is the probability that first dice showed a multiple of 3 and the second dice showed an even number?
- a)1/6
- b)1/3
- c)5/6
- d)1/9
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Ajay rolled two dice together. What is the probability that first dice...
Given:
One dice shows a multiple of 3.
Other dice shows even number.
Concept:
Total number of outcomes in two dice is 36.
Formula used:
P = Favorable outcomes/Total outcomes
Calculation:
There are only 6 such cases as required,
There are only 6 such cases as required,
(3,2), (3,4) (3,6) (6,2) (6,4) (6,6)
∴ Required probability = 6/36 = 1/6
∴ The probability is 1/6.
Most Upvoted Answer
Ajay rolled two dice together. What is the probability that first dice...
To find the probability that the first dice shows a multiple of 3 and the second dice shows an even number, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Number of favorable outcomes:
The first dice can show a multiple of 3 in four ways: 3, 6, 9, or 12. Out of these, 6, 9, and 12 are also even numbers. So, there are a total of 3 favorable outcomes.
Total number of possible outcomes:
When two dice are rolled together, each dice can show any number from 1 to 6, resulting in a total of 6 × 6 = 36 possible outcomes.
Hence, the probability of the first dice showing a multiple of 3 and the second dice showing an even number is given by:
P = (Number of favorable outcomes) / (Total number of possible outcomes)
P = 3 / 36
P = 1 / 12
Therefore, the correct answer is option A) 1/6.
To summarize:
- The first dice can show a multiple of 3 in 4 ways: 3, 6, 9, or 12.
- Out of these, 6, 9, and 12 are also even numbers.
- Hence, there are a total of 3 favorable outcomes.
- When two dice are rolled together, there are 6 × 6 = 36 possible outcomes.
- Therefore, the probability is 3 / 36, which simplifies to 1 / 12.
- The correct answer is option A) 1/6.
Number of favorable outcomes:
The first dice can show a multiple of 3 in four ways: 3, 6, 9, or 12. Out of these, 6, 9, and 12 are also even numbers. So, there are a total of 3 favorable outcomes.
Total number of possible outcomes:
When two dice are rolled together, each dice can show any number from 1 to 6, resulting in a total of 6 × 6 = 36 possible outcomes.
Hence, the probability of the first dice showing a multiple of 3 and the second dice showing an even number is given by:
P = (Number of favorable outcomes) / (Total number of possible outcomes)
P = 3 / 36
P = 1 / 12
Therefore, the correct answer is option A) 1/6.
To summarize:
- The first dice can show a multiple of 3 in 4 ways: 3, 6, 9, or 12.
- Out of these, 6, 9, and 12 are also even numbers.
- Hence, there are a total of 3 favorable outcomes.
- When two dice are rolled together, there are 6 × 6 = 36 possible outcomes.
- Therefore, the probability is 3 / 36, which simplifies to 1 / 12.
- The correct answer is option A) 1/6.
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Community Answer
Ajay rolled two dice together. What is the probability that first dice...
Given:
One dice shows a multiple of 3.
Other dice shows even number.
Concept:
Total number of outcomes in two dice is 36.
Formula used:
P = Favorable outcomes/Total outcomes
Calculation:
There are only 6 such cases as required,
There are only 6 such cases as required,
(3,2), (3,4) (3,6) (6,2) (6,4) (6,6)
∴ Required probability = 6/36 = 1/6
∴ The probability is 1/6.
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Ajay rolled two dice together. What is the probability that first dice showed a multiple of 3 and the second dice showed an even number?a)1/6b)1/3c)5/6d)1/9Correct answer is option 'A'. Can you explain this answer?
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