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Two dice are thrown simultaneously and the sum of the numbers appearing on them is noted. What is the probability that the sum is 12?
- a)1/36
- b)3
- c)36
- d)12/36
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two dice are thrown simultaneously and the sum of the numbers appearin...
Given:
No of possible outcomes when two dice are thrown simultaneously: 6 × 6 = 36
(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Formula used:
Probability = No of favorable outcome ÷ No of total outcomes
Calculation:
No of outcome with sum 12 (6, 6) = 1
∴ Required probability = 1/36
Most Upvoted Answer
Two dice are thrown simultaneously and the sum of the numbers appearin...
Given:
No of possible outcomes when two dice are thrown simultaneously: 6 × 6 = 36
(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Formula used:
Probability = No of favorable outcome ÷ No of total outcomes
Calculation:
No of outcome with sum 12 (6, 6) = 1
∴ Required probability = 1/36
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Community Answer
Two dice are thrown simultaneously and the sum of the numbers appearin...
To find the probability of getting a sum of 12 when two dice are thrown simultaneously, we need to first determine the total number of possible outcomes and then find the number of favorable outcomes.
Total number of outcomes:
When two dice are thrown simultaneously, each die has 6 possible outcomes (numbers 1 to 6). Since there are two dice, the total number of outcomes is 6 * 6 = 36.
Favorable outcomes:
To get a sum of 12, we need to find the number of combinations of two numbers on the dice that add up to 12. There are only two combinations that satisfy this condition: (6, 6) and (5, 7).
Probability calculation:
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes.
Number of favorable outcomes = 2
Total number of outcomes = 36
Probability = Number of favorable outcomes / Total number of outcomes
= 2 / 36
= 1 / 18
However, the options provided in the question are in the form of fractions. To convert the probability to a fraction, we can simplify it.
The fraction 1/18 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 2.
1 ÷ 2 / 18 ÷ 2
= 1/2 / 9
= 1/2 * 1/9
= 1/18
Therefore, the probability of getting a sum of 12 when two dice are thrown simultaneously is 1/18.
The correct answer is option A: 1/36.
Total number of outcomes:
When two dice are thrown simultaneously, each die has 6 possible outcomes (numbers 1 to 6). Since there are two dice, the total number of outcomes is 6 * 6 = 36.
Favorable outcomes:
To get a sum of 12, we need to find the number of combinations of two numbers on the dice that add up to 12. There are only two combinations that satisfy this condition: (6, 6) and (5, 7).
Probability calculation:
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes.
Number of favorable outcomes = 2
Total number of outcomes = 36
Probability = Number of favorable outcomes / Total number of outcomes
= 2 / 36
= 1 / 18
However, the options provided in the question are in the form of fractions. To convert the probability to a fraction, we can simplify it.
The fraction 1/18 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 2.
1 ÷ 2 / 18 ÷ 2
= 1/2 / 9
= 1/2 * 1/9
= 1/18
Therefore, the probability of getting a sum of 12 when two dice are thrown simultaneously is 1/18.
The correct answer is option A: 1/36.
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Two dice are thrown simultaneously and the sum of the numbers appearing on them is noted. What is the probability that the sum is 12?a)1/36b)3c)36d)12/36Correct answer is option 'A'. Can you explain this answer?
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