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What is the output of the following code?
for i in range(1, 6):
print(' ' * (5 - i) + chr(64 + i) * i)
for i in range(1, 6):
print(' ' * (5 - i) + chr(64 + i) * i)
- a)A
BB
CCC
DDDD
EEEEE - b)E
DDD
CCC
BB
A - c)A
AA
AAA
AAAA
AAAAA - d)E
EE
EEE
EEEE
EEEEE
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
What is the output of the following code?for i in range(1, 6): print(...
Answer:
The correct output of the given code is option 'B':
E
DDD
CCC
BB
A
Explanation:
To understand the output of the code, let's analyze the code step by step:
1. The code uses a for loop to iterate over the range from 1 to 6 (exclusive).
2. In each iteration, the code prints a string using the print() function.
3. The string to be printed consists of two parts:
a) The first part is a series of spaces. The number of spaces is determined by the expression `(5 - i)`. The value of `i` increases from 1 to 5, so the number of spaces decreases from 4 to 0.
b) The second part is a series of characters. The character to be printed is determined by the expression `chr(64 + i)`. The value of `i` increases from 1 to 5, so the character changes from 'A' to 'E'. The `chr()` function converts the ASCII value to a character.
c) The number of characters in the second part is determined by the value of `i`. In the first iteration, `i` is 1, so one 'A' is printed. In the second iteration, `i` is 2, so two 'B's are printed. This pattern continues until the fifth iteration, where `i` is 5, so five 'E's are printed.
4. The output is displayed on separate lines due to the newline character added by the print() function.
Based on this analysis, the correct output of the code is:
E
DDD
CCC
BB
A
The correct output of the given code is option 'B':
E
DDD
CCC
BB
A
Explanation:
To understand the output of the code, let's analyze the code step by step:
1. The code uses a for loop to iterate over the range from 1 to 6 (exclusive).
2. In each iteration, the code prints a string using the print() function.
3. The string to be printed consists of two parts:
a) The first part is a series of spaces. The number of spaces is determined by the expression `(5 - i)`. The value of `i` increases from 1 to 5, so the number of spaces decreases from 4 to 0.
b) The second part is a series of characters. The character to be printed is determined by the expression `chr(64 + i)`. The value of `i` increases from 1 to 5, so the character changes from 'A' to 'E'. The `chr()` function converts the ASCII value to a character.
c) The number of characters in the second part is determined by the value of `i`. In the first iteration, `i` is 1, so one 'A' is printed. In the second iteration, `i` is 2, so two 'B's are printed. This pattern continues until the fifth iteration, where `i` is 5, so five 'E's are printed.
4. The output is displayed on separate lines due to the newline character added by the print() function.
Based on this analysis, the correct output of the code is:
E
DDD
CCC
BB
A
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Community Answer
What is the output of the following code?for i in range(1, 6): print(...
The code prints a character pattern where each row contains a repeating character based on the row index, starting from 'E' and descending to 'A'.
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