Civil Engineering (CE) Exam  >  Civil Engineering (CE) Questions  >  Determine the net ultimate bearing capacity (... Start Learning for Free
Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depth
of 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? and
Y, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,
nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2?
Most Upvoted Answer
Determine the net ultimate bearing capacity ( q,,, ) of a square footi...
**Given Data:**
- Size of square footing: 1.5 m * 1.5 m
- Depth of footing: 1.0 m
- Clay deposit consists of two layers:
- Top layer: 1 m thick, c1 = 1.50 x 10^5 N/m², γ1 = 16 kN/m³
- Bottom layer: c2 = 0.5 x 10^5 N/m², γ2 = 15 kN/m³
- ic = 1.0, nc = 3.5, sc = 1.29, dc = 1.27
- Ultimate bearing capacity (q_ult) = 0.8761 x 10^6 N/m²

**Calculating Net Ultimate Bearing Capacity:**

1. Calculate the net ultimate bearing capacity for each layer:
- For the top layer:
- q_ult1 = q_ult * (nc * sc * ic * dc)
- q_ult1 = 0.8761 x 10^6 N/m² * (3.5 * 1.29 * 1.0 * 1.27)
- For the bottom layer:
- q_ult2 = q_ult * (nc * sc * ic * dc)
- q_ult2 = 0.8761 x 10^6 N/m² * (3.5 * 1.29 * 1.0 * 1.27)

2. Calculate the effective stress at the base of each layer:
- For the top layer:
- σ_1 = γ1 * (depth of top layer)
- σ_1 = 16 kN/m³ * 1.0 m
- For the bottom layer:
- σ_2 = γ2 * (depth of bottom layer)
- σ_2 = 15 kN/m³ * 1.0 m

3. Calculate the net ultimate bearing capacity for the square footing:
- q_net = (q_ult1 - σ_1) + (q_ult2 - σ_2)
- q_net = (0.8761 x 10^6 N/m² * (3.5 * 1.29 * 1.0 * 1.27) - (16 kN/m³ * 1.0 m)) + (0.8761 x 10^6 N/m² * (3.5 * 1.29 * 1.0 * 1.27) - (15 kN/m³ * 1.0 m))

4. Convert the net ultimate bearing capacity to kN/m²:
- q_net_kN/m² = q_net / 1000

**Answer:**
The net ultimate bearing capacity of the square footing is 860.1 kN/m².
Explore Courses for Civil Engineering (CE) exam

Similar Civil Engineering (CE) Doubts

Top Courses for Civil Engineering (CE)

Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2?
Question Description
Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2?.
Solutions for Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? defined & explained in the simplest way possible. Besides giving the explanation of Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2?, a detailed solution for Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? has been provided alongside types of Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? theory, EduRev gives you an ample number of questions to practice Determine the net ultimate bearing capacity ( q,,, ) of a square footing of size 1.5 m * 1.5 m which is located at a depthof 1.0 m in a clay deposit consisting of two layers. The top layer is 1 m thick and has c1= 1.50 x 10^5N/m? andY, = 16KN/m?*. The bottom layer has c 2; = 0.5 x 10^5N/m? and Y = 15 kN/m?. Assume that the value of ic, = 1.0,nc, = 3.5 ,sc, = 1.29, dc , = 1.27 and take ultimate bearing capacity = 0.8761 x 10^6 N/m^2 ?ANS 860.1 KN/m^2? tests, examples and also practice Civil Engineering (CE) tests.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev