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An open cubical tank was initially fully filled with water . when the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume of water spilled out .the acceleration was?
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An open cubical tank was initially fully filled with water . when the ...
Tan theta = a/g. And V= 1/3v, then ,a/g = 2/3, then a=2g/3. 

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An open cubical tank was initially fully filled with water . when the ...
Acceleration of the Tank:
- To find the acceleration of the tank, we first need to consider the forces acting on the water in the tank when it is accelerated along one of its sides.

Forces Acting on the Water:
- When the tank is accelerated, an inertial force acts on the water in the opposite direction to the acceleration.
- This inertial force causes the water to spill out of the tank, reducing its volume.

Calculating the Acceleration:
- Let V be the initial volume of water in the tank.
- Since one-third of the volume spills out, the remaining volume of water in the tank after acceleration is 2/3 V.
- This reduction in volume is due to the inertial force caused by the acceleration.
- The acceleration can be calculated using the formula:
Inertial Force = Mass of Water x Acceleration
- Since the tank is open, the mass of water spilled out is equal to the mass of the spilled water.
- The mass of the spilled water can be calculated using the density of water and the volume spilled out.

Final Calculation:
- Once the mass of the spilled water is calculated, the acceleration can be found by dividing the inertial force by the mass of the spilled water.
- This acceleration value will tell us how fast the tank was accelerated along one of its sides for one-third of the water volume to spill out.
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An open cubical tank was initially fully filled with water . when the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume of water spilled out .the acceleration was?
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