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There are 32 new balls and 4 old balls in one bag. If any two balls are picked from the bag, what is the probability of both the balls being new?
- a)248/315
- b)249/315
- c)436/316
- d)436/315
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
There are 32 new balls and 4 old balls in one bag. If any two balls ar...
Given:
There are 32 new balls and 4 old balls in one bag.
Concept:
Number of ways to select ‘a’ out of ‘b’ = bCa = b (b-1)/2 (when a = 2)
Probability = Number of favorable case / Total cases
Calculation:
32 new balls and 4 old balls in one bag:
Both the balls should be new.
∴, Required probability = 32C2 / 36C2
⇒ (32 × 31) / (36 × 35)
⇒ (8 × 31) / (9 × 35)
⇒ 248 / 315
Most Upvoted Answer
There are 32 new balls and 4 old balls in one bag. If any two balls ar...
Given:
There are 32 new balls and 4 old balls in one bag.
Concept:
Number of ways to select ‘a’ out of ‘b’ = bCa = b (b-1)/2 (when a = 2)
Probability = Number of favorable case / Total cases
Calculation:
32 new balls and 4 old balls in one bag:
Both the balls should be new.
∴, Required probability = 32C2 / 36C2
⇒ (32 × 31) / (36 × 35)
⇒ (8 × 31) / (9 × 35)
⇒ 248 / 315
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There are 32 new balls and 4 old balls in one bag. If any two balls are picked from the bag, what is the probability of both the balls being new?a)248/315b)249/315c)436/316d)436/315Correct answer is option 'A'. Can you explain this answer?
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