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ACT Exam  >  ACT Questions  >  Comprehension:Direction: Based on the followi... Start Learning for Free
Comprehension:
Direction: Based on the following information, answer the questions.
For an experiment, a sample of 25 observations from normal distribution with mean 98.6 and s.d. 17.2 was selected. Answer the following questions:
What is P(92 <  < 102)?
  • a)
    0.8115
  • b)
    0.8741
  • c)
    0.7856
  • d)
    0.8834
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Comprehension:Direction: Based on the following information, answer th...
Concept:
If a random sample of size n is taken from a population with mean μ and s.d. σ, then the sample distribution of X (sample mean) has a mean equal to population mean i.e., μ and a s.d. σM
Therefore,  follows standard normal distribution.
Calculation:
We have μ = 98.6, σM=2.86
⇒ - 1.918 < Z < 0.988
= P(- 1.918 < Z < 0.988)
= FZ(0.988) − FZ(−1.918)
= 0.3389 + 0.4726
= 0.8115
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Most Upvoted Answer
Comprehension:Direction: Based on the following information, answer th...
Concept:
If a random sample of size n is taken from a population with mean μ and s.d. σ, then the sample distribution of X (sample mean) has a mean equal to population mean i.e., μ and a s.d. σM
Therefore,  follows standard normal distribution.
Calculation:
We have μ = 98.6, σM=2.86
⇒ - 1.918 < Z < 0.988
= P(- 1.918 < Z < 0.988)
= FZ(0.988) − FZ(−1.918)
= 0.3389 + 0.4726
= 0.8115
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Directions:Read the passages and choose the best answer to each question.PassageNear the end of the 19th century, British engineer Osborne Reynolds ran a set of experiments to observe and predict the transition between laminar (steady) and turbulent flow of a liquid through a pipe. In Reynolds’ experiments, dye was forced through a liquid to show visually when the flow changed from laminar to turbulent. Laminar flow is common only in cases in which the flow channel is relatively small, the fluid is moving slowly, and its viscosity (the degree to which a fluid resists flow under an applied forc e) is relatively high. In turbulent flow, the speed of the fluid at any given point is continuously undergoing changes in both magnitude and direction. Reynolds demonstrated that the transition from laminar to turbulent flow in a pipe depends upon the value of a mathematical quantity equal to the velocity of flow (V ) times the diameter of the tube (D) times the mass density (ρ) of the fluid divided by its absolute viscosity (µ). The “Reynolds number,” as it is called, is determined by the following equation:Several students designed similar experiments to observe flow rates of different liquids. To conduct the experiments, the students were given the following apparatus: Liquid supply tank with clear test section tube and ‘bell mouth’ entrance 1 Rotameter to measure the velocity of flow (flow rate) Tap water • Motor oil 4, 10-ft long smooth pipes of various diameters: 0.25-inch, 0.50-inch, 0.75-inch, 1.0-inchFigure 1 illustrates an approximation of the set-up of each experiment.Figure 2 shows approximate viscosities of the water and motor oils used in the experiments.Experiment 1In Experiment 1, students began with a pipe of diameter 0.25 inches. The pipe was set first at a 15° angle and tap water was released steadily from the tank into the pipe. The velocity of flow (V) was measured. The pipe was then set at a 30° angle, a 45° angle, and a 60° angle, water was released steadily from the tank into the pipe, and the velocity of flow was measured. The process was then repeated for each diameter of pipe using the same amount of water each time. All data were recorded in Table 1. Temperature of the water was held constant at 20°C.Experiment 2In the second experiment, the tap water was replaced by Motor Oil A and the processes were repeated. The results are given in Table 2.Experiment 3In a third experiment, the tap water was replaced by Motor Oil B and the processes were repeated.Q. In Experiment 1, at a 30° angle, flow rate would most likely have been approximately 6.0 ft/s for which new pipe diameter?

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Comprehension:Direction: Based on the following information, answer the questions.For an experiment,a sample of 25 observations from normal distribution with mean 98.6 and s.d. 17.2 was selected. Answer the following questions:What is P(92 << 102)?a)0.8115b)0.8741c)0.7856d)0.8834Correct answer is option 'A'. Can you explain this answer?
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Comprehension:Direction: Based on the following information, answer the questions.For an experiment,a sample of 25 observations from normal distribution with mean 98.6 and s.d. 17.2 was selected. Answer the following questions:What is P(92 << 102)?a)0.8115b)0.8741c)0.7856d)0.8834Correct answer is option 'A'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about Comprehension:Direction: Based on the following information, answer the questions.For an experiment,a sample of 25 observations from normal distribution with mean 98.6 and s.d. 17.2 was selected. Answer the following questions:What is P(92 << 102)?a)0.8115b)0.8741c)0.7856d)0.8834Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Comprehension:Direction: Based on the following information, answer the questions.For an experiment,a sample of 25 observations from normal distribution with mean 98.6 and s.d. 17.2 was selected. Answer the following questions:What is P(92 << 102)?a)0.8115b)0.8741c)0.7856d)0.8834Correct answer is option 'A'. Can you explain this answer?.
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