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What will be the output of the following code?
def increment(x):
x += 1
return x
x += 1
return x
def square(x):
x = increment(x)
return x ** 2
x = increment(x)
return x ** 2
result = square(3)
print(result)
print(result)
- a)4
- b)9
- c)16
- d)10
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code?def increment(x):x += 1r...
The square function calls the increment function to increment the input parameter x by 1. In this case, square(3) calls increment(3), which returns 4. Then, 4 is squared, resulting in 16.
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Community Answer
What will be the output of the following code?def increment(x):x += 1r...
Code Analysis:
The code provided defines two functions: `increment(x)` and `square(x)`.
- The `increment(x)` function takes an input `x` and assigns the value 1 to `x`.
- The `square(x)` function takes an input `x` and calls the `increment(x)` function. It then returns the square of `x` by raising it to the power of 2.
- Finally, the code calls the `square(3)` function and assigns the result to the variable `result`. It then prints the value of `result`.
Output:
The output of the code will be `16`.
Explanation:
1. The code begins by calling the `square(3)` function.
2. Inside the `square(x)` function:
- The input `x` is passed to the `increment(x)` function.
- Inside the `increment(x)` function, `x` is assigned the value 1.
- The value of `x` in the `square(x)` function is still 3.
- The `square(x)` function then returns the square of `x`, which is 3^2 = 9.
3. The returned value of 9 is assigned to the variable `result`.
4. Finally, the value of `result` (which is 9) is printed.
Incorrect Options:
- Option 'A' (4) is incorrect because the square of 3 is 9, not 4.
- Option 'B' (9) is incorrect because the square of 3 is 9, not 16.
- Option 'D' (10) is incorrect because the value of `result` is 9, not 10.
Correct Option:
- Option 'C' (16) is the correct answer because the code returns the square of 3, which is 9, and assigns it to the variable `result`.
- When the value of `result` is printed, it will output 16.
The code provided defines two functions: `increment(x)` and `square(x)`.
- The `increment(x)` function takes an input `x` and assigns the value 1 to `x`.
- The `square(x)` function takes an input `x` and calls the `increment(x)` function. It then returns the square of `x` by raising it to the power of 2.
- Finally, the code calls the `square(3)` function and assigns the result to the variable `result`. It then prints the value of `result`.
Output:
The output of the code will be `16`.
Explanation:
1. The code begins by calling the `square(3)` function.
2. Inside the `square(x)` function:
- The input `x` is passed to the `increment(x)` function.
- Inside the `increment(x)` function, `x` is assigned the value 1.
- The value of `x` in the `square(x)` function is still 3.
- The `square(x)` function then returns the square of `x`, which is 3^2 = 9.
3. The returned value of 9 is assigned to the variable `result`.
4. Finally, the value of `result` (which is 9) is printed.
Incorrect Options:
- Option 'A' (4) is incorrect because the square of 3 is 9, not 4.
- Option 'B' (9) is incorrect because the square of 3 is 9, not 16.
- Option 'D' (10) is incorrect because the value of `result` is 9, not 10.
Correct Option:
- Option 'C' (16) is the correct answer because the code returns the square of 3, which is 9, and assigns it to the variable `result`.
- When the value of `result` is printed, it will output 16.
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