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What will be the output of the following code?
def multiply(a, *args):
result = a
for num in args:
result *= num
return result
result = a
for num in args:
result *= num
return result
result = multiply(2, 3, 4, 5)
print(result)
print(result)
- a)2
- b)60
- c)120
- d)150
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code?def multiply(a, *args):r...
The multiply function multiplies the arguments passed to it. In this case, it is called with arguments 2, 3, 4, and 5. The result is calculated as 2 * 3 * 4 * 5 = 60, which is printed as the output.
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Community Answer
What will be the output of the following code?def multiply(a, *args):r...
Explanation:
The given code defines a function named "multiply" that takes an initial value "a" and a variable number of arguments "*args". The function multiplies the initial value "a" with all the arguments in "*args" and returns the result.
In the main code, the function "multiply" is called with the arguments (2, 3, 4, 5). Here's how the multiplication is done:
- The initial value "a" is 2.
- The first argument in "*args" is 3. So, 2 * 3 = 6.
- The second argument in "*args" is 4. So, 6 * 4 = 24.
- The third argument in "*args" is 5. So, 24 * 5 = 120.
Therefore, the final result is 120.
Output:
The code will output:
Option C) 120
The given code defines a function named "multiply" that takes an initial value "a" and a variable number of arguments "*args". The function multiplies the initial value "a" with all the arguments in "*args" and returns the result.
In the main code, the function "multiply" is called with the arguments (2, 3, 4, 5). Here's how the multiplication is done:
- The initial value "a" is 2.
- The first argument in "*args" is 3. So, 2 * 3 = 6.
- The second argument in "*args" is 4. So, 6 * 4 = 24.
- The third argument in "*args" is 5. So, 24 * 5 = 120.
Therefore, the final result is 120.
Output:
The code will output:
Option C) 120
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