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The data given below shows the marks obtained by various students.

What is the mean marks (Correct up to two decimal places) of given data? 
  • a)
    13.67
  • b)
    14.67
  • c)
    15.33
  • d)
    13.33
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The data given below shows the marks obtained by various students.What...
⇒ n = total frequency
∑fx = Sumoftheproductofmid − intervalvaluesandtheircorrespondingfrequency
Mid value of 10 – 12 = (10 + 12)/2 = 11
Mid value of 12 – 14 = (12 + 14 )/2 = 13
Mid value of 14 – 16 = (14 + 16 )/2 = 15
Mid value of 16 – 18 = (16 + 18 )/2 = 17
Mid value of 18 – 20 = (18 + 20 )/2 = 19

⇒ Mean = 14.67
∴The mean marks of the given data are 14.67
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Most Upvoted Answer
The data given below shows the marks obtained by various students.What...
⇒ n = total frequency
∑fx = Sumoftheproductofmid − intervalvaluesandtheircorrespondingfrequency
Mid value of 10 – 12 = (10 + 12)/2 = 11
Mid value of 12 – 14 = (12 + 14 )/2 = 13
Mid value of 14 – 16 = (14 + 16 )/2 = 15
Mid value of 16 – 18 = (16 + 18 )/2 = 17
Mid value of 18 – 20 = (18 + 20 )/2 = 19

⇒ Mean = 14.67
∴The mean marks of the given data are 14.67
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Community Answer
The data given below shows the marks obtained by various students.What...
⇒ n = total frequency
∑fx = Sumoftheproductofmid − intervalvaluesandtheircorrespondingfrequency
Mid value of 10 – 12 = (10 + 12)/2 = 11
Mid value of 12 – 14 = (12 + 14 )/2 = 13
Mid value of 14 – 16 = (14 + 16 )/2 = 15
Mid value of 16 – 18 = (16 + 18 )/2 = 17
Mid value of 18 – 20 = (18 + 20 )/2 = 19

⇒ Mean = 14.67
∴The mean marks of the given data are 14.67
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The data given below shows the marks obtained by various students.What is the mean marks (Correct up to two decimal places) of given data?a)13.67b)14.67c)15.33d)13.33Correct answer is option 'B'. Can you explain this answer?
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