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Salad dressing A is made up of 30% vinegar and 70% oil, and salad dressing B contains 10% vinegar and 90% oil. If the 2 dressing are combined to produce a salad dressing that is 15% vinegar, dressing A comprises what % of the new dressing?
  • a)
    15%
  • b)
    20%
  • c)
    25%
  • d)
    40%
  • e)
    55%
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres...
Let's assume that the quantity of dressing A used is x and the quantity of dressing B used is y to create the new dressing.
Since we are combining dressing A and dressing B to produce a dressing with 15% vinegar, we can set up the following equation based on the vinegar content:
(0.30 * x + 0.10 * y) / (x + y) = 0.15
Simplifying the equation:
0.30x + 0.10y = 0.15(x + y)
0.30x + 0.10y = 0.15x + 0.15y
0.30x - 0.15x = 0.15y - 0.10y
0.15x = 0.05y
3x = y
This means that the quantity of dressing B used (y) is three times the quantity of dressing A used (x).
To find the percentage of dressing A in the new dressing, we need to calculate the ratio of dressing A to the total dressing (A + B).
Percentage of dressing A = (x / (x + y)) * 100
Substituting y = 3x:
Percentage of dressing A = (x / (x + 3x)) * 100
Percentage of dressing A = (x / 4x) * 100
Percentage of dressing A = (1/4) * 100
Percentage of dressing A = 25%
Therefore, dressing A comprises 25% of the new dressing.
The correct answer is C: 25%.
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Question Description
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