How many integer values of x satisfy the inequality |x - 5| ≤ 2.5?a...
To solve the inequality |x - 5| ≤ 2.5, we can consider two cases:
Case 1: x - 5 ≥ 0
In this case, the absolute value |x - 5| is equal to x - 5.
Substituting this into the inequality, we have x - 5 ≤ 2.5.
By adding 5 to both sides of the inequality, we get x ≤ 7.5.
Case 2: x - 5 < 0
In this case, the absolute value |x - 5| is equal to -(x - 5) = -x + 5.
Substituting this into the inequality, we have -x + 5 ≤ 2.5.
By subtracting 5 from both sides of the inequality and multiplying by -1, we get x ≥ 2.5.
Combining the results from both cases, we have 2.5 ≤ x ≤ 7.5.
To find the number of integer values of x that satisfy the inequality, we can count the integers within this range.
The integers that satisfy the inequality are 3, 4, 5, 6, and 7. (Note that 2.5 and 7.5 are not included since the inequality is not inclusive.)
Therefore, there are 5 integer values of x that satisfy the inequality.
Thus, the correct answer is C: 5.