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The chemical rxn 2O3→3O2 proceeds as O3==(in eqm)O2+O (fast) O+O3→2O2 (slow) What is the rate law expression?
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The chemical rxn 2O3→3O2 proceeds as O3==(in eqm)O2+O (fast) O+O3→2O2 ...
What ans. is given in your book? whether it is a 2nd order rx^n?I have not done this question by trial balance.
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The chemical rxn 2O3→3O2 proceeds as O3==(in eqm)O2+O (fast) O+O3→2O2 ...
R= K[O3]2[O2]-1so it is 1 order reaction
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The chemical rxn 2O3→3O2 proceeds as O3==(in eqm)O2+O (fast) O+O3→2O2 (slow) What is the rate law expression?
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