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What will be the output of the following code?
public class MyClass {
   public static void main(String[] args) {
      int x = 5;
      int y = increment(x);
      System.out.println(y);
   }
   public static int increment(int value) {
      return ++value;
   }
}
  • a)
    5
  • b)
    6
  • c)
    Compilation Error
  • d)
    Runtime Error
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code?public class MyClass { p...
Explanation:
The given code defines a class named "MyClass" with a main method.
The main method initializes an integer variable "x" with the value 5.
Then, it calls the increment method and passes the value of "x" as an argument.
The returned value from the increment method is stored in the variable "y".
Finally, the value of "y" is printed.

Step-by-Step Execution:
1. The main method is called and the variable "x" is initialized with the value 5.
2. The increment method is called, and the value of "x" (i.e., 5) is passed as an argument.
3. In the increment method, the value parameter is received and stored in the variable "value".
4. The value of "value" is returned.
5. The returned value (i.e., 5) is stored in the variable "y".
6. The value of "y" (i.e., 5) is printed using the System.out.println statement.

Output:
The output of the code will be:
6

Explanation:
The output is 6 because the increment method does not actually increment the value passed to it. It simply returns the value as it is. So, when the value 5 is passed to the increment method, it returns 5, and that value is stored in the variable "y". Therefore, the output is 6.
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Community Answer
What will be the output of the following code?public class MyClass { p...
The 'increment' method takes an integer as a parameter, increments it by 1, and returns the incremented value. In the 'main' method, the variable 'x' is assigned the value 5, and the 'increment' method is called with 'x' as an argument. The returned value (6) is then printed.
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