The average weight of students in a class increases by 600 gm when som...
Let the original number of students be 'n' whose average weight is 'x'
Let the number of students added be 'm' and the average weight will be x + 3
We need to find the value of n : m
It is given, average weight of students in a class increased by 0.6 after new students are added.
Therefore,
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The average weight of students in a class increases by 600 gm when som...
Let's assume that there are 'x' original students in the class and 'y' new students who join the class.
Given that the average weight of the students in the class increases by 600 gm when the new students join, we can write the equation:
(x * A) + (y * B) = (x + y) * C
Where A is the average weight of the original students, B is the average weight of the new students, and C is the average weight of all the students in the class after the new students join.
We are also given that the average weight of the new students is 3 kg more than the average weight of the original students. So we can write another equation:
B = A + 3
Substituting the value of B in the first equation, we get:
(x * A) + (y * (A + 3)) = (x + y) * C
Expanding and simplifying, we get:
x * A + y * A + 3y = x * C + y * C
x * A - x * C = y * C - y * A - 3y
x(A - C) = y(C - A - 3)
x/y = (C - A - 3)/(A - C)
Since we are looking for the ratio of the number of original students to the number of new students, we can assume that the number of new students is greater than the number of original students. So the ratio will be in the form of '4 : 1' or 'x : 1'.
Now, let's substitute the values given in the options and see which one satisfies the equation:
For option A: x/y = (C - A - 3)/(A - C) = (C - A - 3)/(A - C) = 1/2
For option B: x/y = (C - A - 3)/(A - C) = (C - A - 3)/(A - C) = 4/1
For option C: x/y = (C - A - 3)/(A - C) = (C - A - 3)/(A - C) = 1/4
For option D: x/y = (C - A - 3)/(A - C) = (C - A - 3)/(A - C) = 3/1
Out of these options, only option B satisfies the equation, so the correct answer is option B: 4 : 1.
The average weight of students in a class increases by 600 gm when som...
Let the original number of students be 'n' whose
average weight is x'
Let the number of students added be 'm' and the
average weight will be x+ 3
We need to find the value of n:m
It is given, average weight of students in a class
increased by 0.6 after new students are added.
Therefore,
[nx +m(x+3)] / n+m = x+0.6
nx + mx + 3m = nx + 0.6n + mx + 0.6m
2.4m= 0.6n
4m=1n
n:m = 4:1