(9) Nidhi and Akash are running along a circular path in the same dire...
**Solution:**
To find the time taken by Nidhi and Akash to reach diametrically opposite points on the circular path, we need to determine the time taken by each person to cover the circumference of the circle.
**Calculating the Time taken by Nidhi:**
Nidhi's speed is given as 7 km/hr.
To find the time taken by Nidhi to cover the circumference of the circle, we can use the formula:
**Time = Distance / Speed**
The distance covered by Nidhi to reach the diametrically opposite point is equal to the circumference of the circle, which is 30 km. Therefore,
Time taken by Nidhi = 30 km / 7 km/hr
**Calculating the Time taken by Akash:**
Akash's speed is given as 13 km/hr.
Similarly, to find the time taken by Akash to cover the circumference of the circle, we can use the formula:
**Time = Distance / Speed**
The distance covered by Akash to reach the diametrically opposite point is equal to the circumference of the circle, which is 30 km. Therefore,
Time taken by Akash = 30 km / 13 km/hr
**Calculating the LCM of the Times:**
To find the time at which Nidhi and Akash are diametrically opposite to the starting point, we need to find the least common multiple (LCM) of their respective times.
LCM (Time taken by Nidhi, Time taken by Akash)
To calculate the LCM, we can first express the times in their simplest form:
Time taken by Nidhi = 30/7 hours = 4 2/7 hours
Time taken by Akash = 30/13 hours = 2 4/13 hours
Now, we can find the LCM of 4 2/7 and 2 4/13.
**Finding the LCM:**
To find the LCM, we can convert the mixed fractions to improper fractions:
4 2/7 = (4 * 7 + 2) / 7 = 30/7
2 4/13 = (2 * 13 + 4) / 13 = 30/13
Now, we can find the LCM of 30/7 and 30/13.
To find the LCM, we can use the formula:
LCM = (Product of the numbers) / (GCD of the numbers)
The product of 30/7 and 30/13 = 900/91
To find the GCD of 30/7 and 30/13, we can simplify the fractions:
30/7 = 30/7 = 15/7
30/13 = 30/13 = 90/13
Now, we can find the GCD of 15/7 and 90/13.
To find the GCD, we can use the Euclidean algorithm:
15/7 = 2 + (1/7)
90/13 = 6 + (6/13)
Now, we can continue the Euclidean algorithm:
15/7 = 2 + (1/7)
90/13 = 6 + (6/13)
7/1 = 7 + (0/1)
13/6 = 2 + (1/6)
Since the
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